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3 years ago

Total surface area of the drawing

Mathematics

1 answer:

Crazy boy [7]3 years ago

4 0

The pentagon's area is the sum of the 5 triangles that comprise it. This is

$5( \frac{1}{2}bh) \times 2=5(9)(6.2)= 279$

where the factor of 2 accounts for the top and bottom. The walls have an area of 5 rectangles

$5(bh)=5(9)(6)=270 \\ \\ 279+270=549km^2$

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if you draw one card from a standard deck, what is the probability of drawing a diamond or a red card?

Aleks [24]

Answer:

3/4 probability

probability to draw a red card = 11/26

probability to draw a diamond =1/4

probability of drawing one or other card = 35/52

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4 0

3 years ago

If the units for x are years, and x = 5 represents the year 2015, what is the y-value for 2010?

Darya [45]

Given:

The given graph passes through the points (-3,4) and (3,2)

The x - axis represents the years. The value x = 5, year 2015.

We need to determine the y - value for 2010.

Slope:

The slope of the line can be determined using the formula,

$m=\frac{y_2-y_1}{x_2-x_1}$

Substituting the points (-3,2) and (3,2), we get;

$m=\frac{2-4}{3+3}$

$m=\frac{-1}{3}$

Thus, the slope of the line is $m=\frac{-1}{3}$

y - intercept:

The y - intercept in the graph is the point in the line that crosses the y - axis.

Thus, from the graph, it is obvious that the y - intercept is b = 3.

Equation of the line:

The equation of the line can be determined using the formula,

$y=mx+b$

Substituting the values, we have;

$y=-\frac{1}{3}x+3$

Thus, the equation of the line is $y=-\frac{1}{3}x+3$

The y - value for 2010:

Since, it is given that x = 5 represents 2015 and 2010 is 5 years before 2010.

Hence, the value of x for 2010 is given by

$x=5-5=0$

Thus, x = 0 represents the year 2010.

To determine the y - value, let us substitute x = 0 in the equation $y=-\frac{1}{3}x+3$ , we have;

$y=-\frac{1}{3}(0)+3$

$y=3$

Thus, for 2010 the value of y is 3.

5 0

2 years ago

How would I add the fractions? <img src="https://tex.z-dn.net/?f=-2%2F5%20%2B%202%2F3p%20%2B1%2F3p%20%3D%202p%20-%2016%2

LiRa [457]

$\bf -\cfrac{2}{5}+\cfrac{2}{3}p+\cfrac{1}{3}p=2p-\cfrac{16}{5}\implies \stackrel{\textit{LCD of 15}}{-\cfrac{2}{5}+\cfrac{2p}{3}+\cfrac{p}{3}}=\stackrel{\textit{LCD of 5}}{2p-\cfrac{16}{5}}
\\\\\\
\cfrac{(3\cdot -2)+(5\cdot 2p)+(5\cdot p)}{15}=\cfrac{(5\cdot 2p)-16}{5}
\\\\\\
\cfrac{-6+10p+5p}{15}=\cfrac{10p-16}{5}\impliedby \textit{now we cross-multiply}
\\\\\\
-30+50p+25p=150p-240\implies -30+240=150p-75p
\\\\\\
210=75p\implies \cfrac{210}{75}=p\implies \cfrac{14}{5}=p$