The linear equation representing the above said pair of points is "y=12x+9"
Step-by-step explanation:
The given set of points are
x Y
1 21
2 33
3 45
4 57
For finding the linear equation for the given sets of value
We must know the generic form of a linear equation is y=m*x + c
m= slope of the line where y= Δy/Δx
Δy= change in y value
Δx= change in x value
Thus slope ”m” = 33-21/2-1 = 12
we put slope “m” in the equation which becomes y=12x+c
Now we put any of the set value in the equation
33= 12*2+c ∴ c=9
Hence required linear equation is y=12x+9
Answer:
<h2>Less than 0.84</h2>
Step-by-step explanation:
- Convert all numbers to decimals
- 85% --> 0.85
- 0.88 --> 0.88
Since these are the top three, the rest of the competitors are less than 0.84.
The gradient of the perpendicular line would be the negative reciprocal of the original line. Therefore the gradient of the perpendicular line would be -2/5x.
Since we know y=mx+c, ∴y=-2/5x+c. Sub in the x and y values of the given point and we get that c=26/5.
The perpendicular equation would be y=-2/5x+26/5.
I hope I got this right.
Given that the sample size is 12, thus the degree of freedom = 12 - 1 = 11.
Using technology, the p value of the t statistic, t = 2.028 is 0.9663.
Answer:
4x² + 4y² + 8xy
Step-by-step explanation:
( 2x + 2y ) ( 2x + 2y ) = ( 2x + 2y )²
Formula : -
( a + b )² = a² + b² + 2ab
Here,
a = 2x
b = 2y
( 2x + 2y )²
= ( 2x )² + ( 2y )² + 2 ( 2x ) ( 2y )
= 2²x² + 2²y² + 8xy
= 4x² + 4y² + 8xy
