Answer:
y=t−1+ce
−t
where t=tanx.
Given, cos
2
x
dx
dy
+y=tanx
⇒
dx
dy
+ysec
2
x=tanxsec
2
x ....(1)
Here P=sec
2
x⇒∫PdP=∫sec
2
xdx=tanx
∴I.F.=e
tanx
Multiplying (1) by I.F. we get
e
tanx
dx
dy
+e
tanx
ysec
2
x=e
tanx
tanxsec
2
x
Integrating both sides, we get
ye
tanx
=∫e
tanx
.tanxsec
2
xdx
Put tanx=t⇒sec
2
xdx=dt
∴ye
t
=∫te
t
dt=e
t
(t−1)+c
⇒y=t−1+ce
−t
where t=tanx
Answer:
12.33
Step-by-step explanation:
6x - 2 + 9x - 3 = 180° (linear pair)
6x + 9x - 2 - 3 = 180°
15x - 5 = 180°
15x = 180 + 5
15x = 185
x = 185/15
x = 12.33
hope this helps you!
Answer:
36,686
Step-by-step explanation:
5.88 x 12 over 10 = 240
240 x 26 = 36,686
The answer is 750000000000
