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tatuchka [14]
4 years ago
7

Please solve for x. Show the process (steps). 4x = 40​

Mathematics
2 answers:
rosijanka [135]4 years ago
5 0

Answer:

x = 10

Step-by-step explanation:

4x = 40

you divide both sides by 4

and it gets you

x = 10

hope this helps

lutik1710 [3]4 years ago
3 0

Answer:

x=10

Step-by-step explanation:

lets reverse engineer this. 4x=40. What is known in this? We know 40 is the unit amount of 4x. So we need to find out what x is, than multiply it by 4. We can do this by doing the opposite of multiplying, which is dividing! So we divide 4 by 40, which we get the answer 10! We know this is the correct answer because we can factor it into the equation. So 4*10=40!!! hope this helped!!!

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What is the solution to 3x^2 + 4x + 8 = 0?
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D) x = -2 ± 2i√5 / 3

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A conical water tank with vertex down has a radius of 13 feet at the top and is 21 feet high. If water flows into the tank at a
VLD [36.1K]

Answer:

\frac{dh}{dt}\approx0.08622\text{ ft/min}

Step-by-step explanation:

We know that the conical water tank has a radius of 13 feet and is 21 feet high.

We also know that water is flowing into the tank at a rate of 30ft³/min. In other words, our derivative of the volume with respect to time t is:

\frac{dV}{dt}=\frac{30\text{ ft}^3}{\text{min}}

We want to find how fast the depth of the water is increasing when the water is 17 feet deep. So, we want to find dh/dt.

First, remember that the volume for a cone is given by the formula:

V=\frac{1}{3}\pi r^2h

We want to find dh/dt. So, let's take the derivative of both sides with respect to the time t. However, first, let's put the equation in terms of h.

We can see that we have two similar triangles. So, we can write the following proportion:

\frac{r}{h}=\frac{13}{21}

Multiply both sides by h:

r=\frac{13}{21}h

So, let's substitute this in r:

V=\frac{1}{3}\pi (\frac{13}{21}h)^2h

Square:

V=\frac{1}{3}\pi (\frac{169}{441}h^2)h

Simplify:

V=\frac{169}{1323}\pi h^3

Now, let's take the derivative of both sides with respect to t:

\frac{d}{dt}[V]=\frac{d}{dt}[\frac{169}{1323}\pi h^3}]

Simplify:

\frac{dV}{dt}=\frac{169}{1323}\pi \frac{d}{dt}[h^3}]

Differentiate implicitly. This yields:

\frac{dV}{dt}=\frac{169}{1323}\pi (3h^2)\frac{dh}{dt}

We want to find dh/dt when the water is 17 feet deep. So, let's substitute 17 for h. Also, let's substitute 30 for dV/dt. This yields:

30=\frac{169}{1323}\pi (3(17)^2)\frac{dh}{dt}

Evaluate:

30=\frac{146523}{1323}\pi( \frac{dh}{dt})

Multiply both sides by 1323:

39690=146523\pi\frac{dh}{dt}

Solve for dh/dt:

\frac{dh}{dt}=\frac{39690}{146523}\pi

Use a calculator. So:

\frac{dh}{dt}\approx0.08622\text{ ft/min}

The water is rising at a rate of approximately 0.086 feet per minute.

And we're done!

Edit: Forgot the picture :)

3 0
3 years ago
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