Something u need to do dude
<span>the limit as x approaches -3 of [g(x)-g(-3)]over(x+3) is the same as the derivative, or slope, of g(x) at the point x=-3, or g'(-3).
Since you are given the equation of the tangent line, the answer is just the slope of that line.
</span><span>2y+3=-(2/3)(x-3)
</span><span>6y+9=-2(x-3)
6y+9=-2x+6
6y=-2x-3
y= (-2x-3)/6
slope is -2/6 = </span>
-320. The negative sign represents loss. In all of the other cases, values are either being added or not changed at all.
4 to he power of 1/2 is 2
I think thats because its 1/2 of 2
Sorry if I'm wrong
Hope this helps
21-3= 18 and 18 divided by 6 equals 3 so v=3