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Dominik [7]
3 years ago
14

PLz help.

Mathematics
2 answers:
Ahat [919]3 years ago
5 0

Answer:

a=6cm

Step-by-step explanation:

Semmy [17]3 years ago
4 0

Answer:  6\ cm

Step-by-step explanation:

Given : The formula for the volume of a cube is :

V=s^3

The volume of a cube = 216\ cm^3

Substitute V= 216 in the above formula , we get

216=s^3

Taking cube root on both the sides , we get

\sqrt[3]{216}=s\\\\\Rightarrow\ s= \sqrt[3]{6^3}=6

Hence, the side length of cube= 6\ cm

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Step-by-step explanation:

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2 years ago
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Paul [167]
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3 years ago
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Based on the family the graph below belongs to, which equation could represent the graph? image below.
natka813 [3]

Answer:

y = 1/x+2 + 3

Step-by-step explanation:

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8 0
3 years ago
Please answer this and will marked as brainlist ​
xeze [42]
<h3>Answer: 1</h3>

where x is nonzero

=======================================================

Explanation:

We'll use two rules here

  • (a^b)^c = a^(b*c) ... multiply exponents
  • a^b*a^c = a^(b+c) ... add exponents

------------------------------

The portion [ x^(a-b) ]^(a+b) would turn into x^[ (a-b)(a+b) ] after using the first rule shown above. That turns into x^(a^2 - b^2) after using the difference of squares rule.

Similarly, the second portion turns into x^(b^2-c^2) and the third part becomes x^(c^2-a^2)

-------------------------------

After applying rule 1 to each of the three pieces, we will have 3 bases of x with the exponents of (a^2-b^2),  (b^2-c^2) and (c^2-a^2)

Add up those exponents (using rule 2 above) and we get

(a^2-b^2)+(b^2-c^2)+(c^2-a^2)

a^2-b^2+b^2-c^2+c^2-a^2

(a^2-a^2) + (-b^2+b^2) + (-c^2+c^2)

0a^2 + 0b^2 + 0c^2

0+0+0

0

All three exponents add to 0. As long as x is nonzero, then x^0 = 1

4 0
3 years ago
Starting at the park, Jake bikes 3 blocks north, 4 blocks east, 4 blocks south, 7 blocks west, and 1 block north. How many block
yan [13]
I'll use a coordinate plane for this since it's easier (for me) :)

Red = park
Blue = his trail
Pink = distance from park = 3

Hope this helped! Please comment or DM me if you have anymore questions or don't understand :)

7 0
3 years ago
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