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2 years ago

In parallelogram NPQR if m&NPQ=125° find m&PQR.

Mathematics

1 answer:

denis23 [38]2 years ago

8 0

Answer:

Step-by-step explanation:

(360 - 125 - 125) / 2 = 55

Opposite angles are the same in a parallelogram.

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Solve each quadratic equation. Show your work. 4x^2=100

ZanzabumX [31]

Hello there!

4x² = 100

We wanna start by dividing both sides by 4

4x²/4 = 100/4

x² = 25

Now we can take square root

x = +/-√25

x = 5 or x = -5

As always, it is my pleasure to help students like you!

4 0

3 years ago

If stamps are $0.30 how many stamps can Janice buy with $7.20

snow_lady [41]

Divide the total amount of money Janice has by the cost of the stamps.

$7.20 / $0.30 = 24

Janice can buy 24 stamps.

7 0

3 years ago

Pleaseeeeeee help mee

BlackZzzverrR [31]

Answer:

The solution of the given trigonometric equation

$x = \frac{\pi }{6}$

Step-by-step explanation:

Step(i):-

Given

$cos( 3x - \frac{\pi }{3} ) = \frac{\sqrt{3} }{2}$

$cos( 3x - \frac{\pi }{3} ) = cos (\frac{\pi }{6} )$

$3x - \frac{\pi }{3} = \frac{\pi }{6}$

$3x - \frac{\pi }{3 } + \frac{\pi }{3} = \frac{\pi }{6} + \frac{\pi }{3}$

$3x = \frac{2\pi +\pi }{6} = \frac{3\pi }{6} = \frac{\pi }{2}$

$x = \frac{\pi }{6}$

Step(ii):-

The solution of the given trigonometric equation

$x = \frac{\pi }{6}$

verification :-

$cos( 3x - \frac{\pi }{3} ) = \frac{\sqrt{3} }{2}$

put $x = \frac{\pi }{6}$

$cos( 3(\frac{\pi }{6}) - \frac{\pi }{3} ) = \frac{\sqrt{3} }{2}$

$cos (\frac{\pi }{6} ) = \frac{\sqrt{3} }{2} \\\\\frac{\sqrt{3} }{2} = \frac{\sqrt{3} }{2}$

Both are equal

∴The solution of the given trigonometric equation

$x = \frac{\pi }{6}$

4 0

2 years ago

I’d you could help I’d appreciate it

arlik [135]

Answer:grater than 8 less than 9

Step-by-step explanation:

had the same question

6 0

3 years ago

Please help. will mark brainliest. What is the value of x? Show all of your work.

AveGali [126]

Answer:

9 cm

Step-by-step explanation:

$\sqrt{117} ^{2} - 6^{2} = x^{2}$

$81 =x^{2}$

$\sqrt{81} = x$

9 cm = x

6 0

3 years ago