Triangles with height
and base
, with
have area
.
Such cross sections with the base of the triangle in the disk
(a disk with radius 5) have base with length

i.e. the vertical (in the
plane) distance between the top and bottom curves describing the circle
.
So when
, the cross section at that point has base

so that the area of the cross section would be 6^2/2 = 18.
In case it's relevant, the entire solid would have volume given by the integral

Answer:
CD=10.15m
Step-by-step explanation:
<u>Find the distance of BC.</u>
Tan(40)=55/BC
BC=65.55m
<u>Find the distance of BD.</u>
Tan(36)=55/BD
BD=75.70m
<u>Use BC and BD to find CD</u>
BD-BC=CD
75.70-65.55=CD
CD=10.15m