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34kurt
3 years ago
9

Solve for E 4/3=6e _ 5/3

Mathematics
1 answer:
pav-90 [236]3 years ago
6 0

Answer:

38.5

Step-by-step explanation:

Lets say, first number = x



Second number = 3x+7



Total = 49




(x)+(3x+7)= 49



4x+7 = 49



4x = 42



x = 42/4



x= 10.5




x= 10.5



3x+7 = 3(10.5)+7 = 38.5




Hope this helps!!

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C. x < 25 and x ≥ 0

Step-by-step explanation:

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The sum of x and 5 is 12. What is the value of x? Enter your answer in the box as a fraction in simplest form. x =
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This might help it has tons of different problems for your subject.


https://www.wyzant.com/resources/lessons/math/algebra/calculators/proportion

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Suppose that we don't have a formula for g(x) but we know that g(3) = −5 and g'(x) = x2 + 7 for all x. (
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So it tells us that g(3) = -5 and g'(x) = x^2 + 7.

So g(3) = -5 is the point (3, -5)
Using linear approximation
g(2.99) is the point (2.99, g(3) + g'(3)*(2.99-3))

now we just need to simplify that
(2.99, -5 + (16)*(-.01)) which is (2.99, -5 + -.16) which is (2.99, -5.16)
So g(2.99) = -5.16 

Doing the same thing for the other g(3.01)
(3.01, g(3) + g'(3)*(3.01-3))
(3.01, -5 + 16*.01) which is (3.01, -4.84)
So g(3.01) = -4.84

So we have our linear approximation for the two. 

If you wanted to, you could check your answer by finding g(x).  Since you know g'(x), take the antiderivative and we will get 
g(x) = 1/3x^3 + 7x + C
Since we know g(3) = -5, we can use that to solve for C
1/3(3)^3 + 7(3) + C = -5 and we find that C = -35
so that means g(x) = (x^3)/3 + 7x - 35

So just to check our linear approximations use that to find g(2.99) and g(3.01)

g(2.99) = -5.1597
g(3.01) = -4.8397

So as you can see, using the linear approximation we got our answers as
g(2.99) = -5.16
g(3.01) = -4.84
which are both really close to the actual answer.  Not a bad method if you ever need to use it. 
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Which step is the same when constructing an inscribed square and an inscribed regular hexagon?
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After the construction of a circle, we have to "Set the compass to the radius of the circle" so, option C is correct.

<h3>What is a regular hexagon?</h3>

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