Answer:
A: 0.1475 , B: 0.3389
Explanation:
a. Probability Refrigerator purchased from store lasts more than 15 years :
Prob(refrigerator purchase from A) and Prob(refrigerator from A life > 15 years) + .........Prob(refrigerator purchase from D) and Prob(refrigerator from D life >15 years)
(0.40x0.1)+(0.25x0.20)+(0.15x0.05)+(0.20x0.25) = 0.04+0.05+0.0075+0.05 = 0.1475
b. Refrigerator last > 15 years given , Probability it is from B :
[ Prob (B Purchase) . Prob (life > 15, given from B) ] / Prob (Life > 15)
P (B/15) = [P(B).P(15/B)] / [P15] {Bayes Theorum}
= [(0.25)(0.20)] / 0.1475 = 0.05 / 0.1475
= 0.3389
Answer:
Adjustments for enterprise fund-basis statements from their original modified accrual basis would not be included in the required reconciliation of the Governmental Fund Balance Sheet to the governmental activities Statement of Net Position.
Answer:
Dr cash $407,000
Cr bonds payable $407,000
July 1
Dr interest expense $ 18,315.00
Cr cash $ 18,315.00
December 31
Dr interest expense $ 18,315.00
Cr interest payable $ 18,315.00
Explanation:
The bond was issued at face value of $407,000 which means that cash of $407,000 was received which is to be debited to cash account and bonds payable account credited for the same amount.
On July1 ,interest coupon of $ 18,315.00 ($407,000*8%*6/12) was paid which means that interest expense is debited with $ 18,315.00 while cash is credited.
On 31 December ,interest coupon of $ 18,315.00 ($407,000*8%*6/12) was due which means that interest expense is debited with $ 18,315.00 while interest payable is credited.
Answer:
c. Work sample tests
Explanation:
Based on the information provided within the question it can be said that the best test to give an individual in this scenario would be a Work sample tests. These are tests that have been specifically designed in order to see if an individual has the ability to do an assigned job and then be able to evaluate their performance. This evaluation will give the employer an idea of how they will perform in the actual job position.
