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Finger [1]
3 years ago
7

1. There are 25 students who started computer programming in elementary school and 25 students who started computer programming

in middle school. The first group had a mean final project grade of 95% and the second group had a mean final project grade of 92%.
The line plot shows the differences after 10 rerandomizations. Determine whether the difference in the means of the two groups is significant based on the line plot. Explain your answer.

Mathematics
1 answer:
mart [117]3 years ago
6 0

Answer:

The difference in the means of the two groups is significant based on the line plot.



Step-by-step explanation:

Given that n1 = 25 and n2 =25 which are the students who started computer programming in elementary and middle school respectively.

Let x bar represent average for elementary and y bar for middle school.

H0: x bar = y bar

Ha: x bar not equals y bar

(Two tailed test)

The line plot gives the differences of sample size 10

Let d = difference = |x bar-y bar|

Then

    Total

     

d 1 2 3 4  

Freq 1 2 4 3 10

d*f 1 4 12 12 29

d^2 *f 1 8 36 48 93

     

Mean d 2.9    

Var d 0.89    

Std dev d 0.943398113    

Std error d 0.314466038    

     

Test statistic 9.221981556    

df 9    

p <0.0001    

Since p < 0.05, at 95% level we conclude that there is a significant difference between the two means.


The line plot shows the differences

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Answer:

(10111)_2 = (23)_{10}

Step-by-step explanation:

(10111)_2 = (1 \times 2^4) + (0 \times 2 ^3) + (1 \times 2^2) + (1 \times 2) + (1 \times 2^0)

            = 16 + 0 + 4 + 2 + 1\\=23

4 0
3 years ago
A rectangle has a length of 9.00 inches and a width of 4.25 inches. What is the area in square inches? Round to the correct sign
Gwar [14]
Both numbers (9.00 and 4.25) have three sig-figs. This means that the final answer will have three sig-figs as well.

Multiply the numbers to get: 9.00*4.25 = 38.25 which rounds to 38.3 because the answer must have three sig-figs. 

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Overall, the final answer is 38.3 square inches. 
4 0
3 years ago
Select the correct answer. . Which value of x makes this equation true? -12x - 2(x + 9) = 5(x + 4) ОА. 13/19 OB. -1/3 OC. -2 OD.
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Answer:

B -1/3

Step-by-step explanation:

4 0
3 years ago
P(x) = x^4+ax^3-x^2+bx-12 has factors of (x-2) and (x+1). Solve the equation P(x)=0​
Feliz [49]

Answer:

because P(x) has factors of (x-2) and (x+1) => x = 2 and x = -1 are the solutions of P(x)

so we have:

\left \{ {{2^{4}+2^{3}a-2^{2}+2b-12   =0} \atop {1-a-1-b-12=0}} \right.\\=>\left \{ {{8a+2b=0} \atop {a+b=-12}} \right.\\\left \{ {{4a+b=0} \atop {a+b=-12}} \right.\\\left \{ {{a=4} \atop {b=-16}} \right.

=> P(x)=x^{4} + 4x^{3}-x^{2} -16x-12

With P(x) = 0

=> x^{4}+4x^{3}-x^{2} -16x-12 = 0

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Step-by-step explanation:

5 0
3 years ago
Please help me on this!
denis23 [38]

Answer:

The Proof is given below.

Step-by-step explanation:

Given:

P is the center of Circle

∠ONE ≅ ∠TEN

To Prove:

∠5 ≅ ∠6

Proof:

Exterior Angle Theorem:

Exterior Angle Property of a Triangle states that measure of exterior angle of a triangle is equals to the sum of measures of its interior opposite angles.

STATEMENT                                                   REASON

1. So In ΔONE,

\angle 5=\angle ONE+\angle 2     1. Exterior Angle Property of a Triangle.

2. Similarly In ΔTEN,

\angle 6=\angle TEN+\angle 1      2. Exterior Angle Property of a Triangle.

3. But , ∠ONE ≅ ∠TEN                                 3. Given

4. And P is the center of circle So

PN=PE                                             4.radius of same circle

5. ΔPEN is an Isosceles triangle,

∴ ∠ 1 ≅ ∠ 2                                                     5. Isosceles triangle property

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5 0
3 years ago
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