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ipn [44]
3 years ago
12

Help with Geometric Functions please

Mathematics
1 answer:
aliina [53]3 years ago
5 0
So
a. so 100-1/10 of 100 or 100-10=90
then second dose minus 10% or 90-9=81
third dose 81 minus 10%=81-8.1=72.9
fourth dose 72.9 minus 10% or 72.9-7.29=65.61

so after 4th dose only 65.61% are left

b. so to get it to 5% you do alot and find that it takes 27 tries to get the percent down to 5.2% and 28 doses to get it to 4.7%
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0.9 in percentage is 90%
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4 years ago
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What is the solution of the equation 3x + 5 + 2x - 12
ss7ja [257]

Answer:

7/5

Step-by-step explanation:

3x + 5 + 2x - 12 = 0

5x - 7 = 0

5x = 7

x = 7/5

5 0
2 years ago
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What is the least common multipul of 6 and 8?
Bogdan [553]

Answer:

Step-by-step explanation:

24

The LCM of 6 and 8 is 24. To find the least common multiple (LCM) of 6 and 8, we need to find the multiples of 6 and 8 (multiples of 6 = 6, 12, 18, 24; multiples of 8 = 8, 16, 24, 32) and choose the smallest multiple that is exactly divisible by 6 and 8, i.e., 24.

5 0
3 years ago
Find the area of each sector shown (the shaded section)
mihalych1998 [28]

Answer:

The area of the sector (shaded section) is 29.51 m^{2}.

Step-by-step explanation:

Area of a sector = (θ ÷ 360) \pir^{2}

where θ is the central angle of the sector, and r is the radius of the circle.

From the diagram give, diameter of the circle is 26 m. So that;

r = \frac{diameter}{2}

 = \frac{26}{2} = 13 m

θ = 360 - (180 + 160)

  = 360 - 340

  = 20^{o}

Thus,

area of the given sector = \frac{20}{360} x \frac{22}{7} x (13)^{2}

                                        = \frac{20}{360} x x \frac{22}{7} x 169

                                         = 29.5079

The area of the sector (shaded section) is 29.51 m^{2}.

4 0
3 years ago
Two ropes are attached to a large ballon in a parade. The people holding the ropes are 40 feet apart,and the angle between the t
qaws [65]

Ropes are 9.63 meters ans 8.178 meters.

<u>Step-by-step explanation:</u>

Step 1 :

List all the given things

         Distance between people holding ropes = 40 =(40*0.3048) meters = 12.192 meters

         Angle between two ropes = 86 degrees

         Angle of elevation of one rope = 42 degrees

Step 2 :

Two angles of triangle are already given so third angle can be calculated as -  

            Third angle = 180 - ( 86 + 42 ) = 52 degrees

Step 3 :

As we know all three angles we will apply sine rule now, which is

\frac{a}{sine A} = \frac{b}{sine B} = \frac{c}{sine C}

Step 4 :

By putting values, we have

\frac{a}{sine 52} = \frac{b}{sine 42} = \frac{12.192}{sine 86}

Step 5 : Calculating a and b

a = 12.192 * \frac{sine 52}{sine 86}   ,   b = 12.192 * \frac{sine 42}{sine 86}      

Step 6 :

By putting values of all sine and calculating we get,

a = 9.63 meters and b = 8.178 meters                                

4 0
3 years ago
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