All categories

2 years ago

Find the measures of angles of triangle DEF

Mathematics

2 answers:

Alchen [17]2 years ago

8 0

Answer:

<h3>Angle E = 90° </h3><h3>Angle D= 55° </h3><h3>Angle F = 35° </h3>

Sum of all the angles of a triangle = 180° ( angle sum property).

Angle D + Angle E + Angle F = 180°

8x - 1 + 5x + 90° = 180°

8x + 5x + 89 = 180

13x = 180 - 89

13x = 91

x = 7.

Angle D = 8x - 1

= 8(7)-1

= 56 - 1

= 55

Angle E = 90° ( given)

Angle F = 5x

= 5 * 7

= 35

GREYUIT [131]2 years ago

5 0

Answer:

m∠E: 90°

m∠D: 55°

m∠F: 35°

Step-by-step explanation:

Since the interior angles of a right triangle sum up to 180°, the sum of angles D, E, F will equal 180°. We can then form an equation from that information.

$90+(8x-1)+5x=180\\13x-1=90\\13x=91\\x=7$

From this, we can plug in the variable.

$mE=90\\mD=55\\mF=35$

You might be interested in

A child weighing 59 lb has a bad infection and is to be given Cefaclor.

cricket20 [7]

Answer:

Step-by-step explanation:

59:2,2=26,81

15*26,81:250=1,6086

6 0

3 years ago

Questions are in the picture

gtnhenbr [62]

The closest point is (3.5, 1.9) and the distance is 1.96 units

<h3>How to determine the point and the distance?</h3>

The coordinate is given as:

(4, 0)

The equation of the function is

y = √x

The distance between two points is calculated using

d = √(x2 - x1)^2 + (y2 - y1)^2

So, we have the following points

(x1, y1) = (4, 0) and (x2, y2) = (x, 0)

This gives

d = √(x - 4)^2 + (√x - 0)^2

Evaluate the difference

d = √(x - 4)^2 + (√x)^2

Evaluate the exponent

d = √x^2 - 8x + 16 + x

Evaluate the like terms

d = √x^2 - 7x + 16

Next, we differentiate using a graphing calculator

d' = (2x - 7)/[2√(x^2 - 7x + 16)]

Set to 0

(2x - 7)/[2√(x^2 - 7x + 16)] = 0

Cross multiply

2x - 7 = 0

Add 7 to both sides

2x = 7

Divide by 2

x = 3.5

So, we have:

Substitute x = 3.5 in y = √x

y = √3.5

Evaluate

y = 1.9

So, the point is (3.5, 1.9)

The distance is then calculated as:

d = √(x2 - x1)^2 + (y2 - y1)^2

This gives

d = √(3.5 - 4)^2 + (1.9 - 0)^2

Evaluate

d = 1.96

Hence, the closest point is (3.5, 1.9) and the distance is 1.96 units

Read more about distance at:

brainly.com/question/23848540

#SPJ1

3 0

2 years ago

a Baker's going to make 24 blueberry pie she wants to make sure that each by contains 3.5 cups of blueberries how many cups of b

Leokris [45]

She is going to need 84 cups of blueberries. 3.5*24= 84 i believe :)

8 0

3 years ago

A random sample of 20 students yielded a mean of ¯x = 72 and a variance of s2 = 16 for scores on a college placement test in mat

Helen [10]

Answer:

The 98% confidence interval for the variance in the pounds of impurities would be $8.400 \leq \sigma^2 \leq 39.827$ .

Step-by-step explanation:

1) Data given and notation

$s^2 =16$ represent the sample variance

s=4 represent the sample standard deviation

$\bar x$ represent the sample mean

n=20 the sample size

Confidence=98% or 0.98

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

The Chi square distribution is the distribution of the sum of squared standard normal deviates .

2) Calculating the confidence interval

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

On this case the sample variance is given and for the sample deviation is just the square root of the sample variance.

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

$df=n-1=20-1=19$

Since the Confidence is 0.98 or 98%, the value of $\alpha=0.02$ and $\alpha/2 =0.01$ , and we can use excel, a calculator or a table to find the critical values.

The excel commands would be: "=CHISQ.INV(0.01,19)" "=CHISQ.INV(0.99,19)". so for this case the critical values are:

$\chi^2_{\alpha/2}=36.191$

$\chi^2_{1- \alpha/2}=7.633$

And replacing into the formula for the interval we got:

$\frac{(19)(16)}{36.191} \leq \sigma^2 \leq \frac{(19)(16)}{7.633}$

$8.400 \leq \sigma^2 \leq 39.827$

So the 98% confidence interval for the variance in the pounds of impurities would be $8.400 \leq \sigma^2 \leq 39.827$ .

7 0

3 years ago

Solve the equation and graph the solution(s), if possible. 9|4p + 2| + 8 = 35

Cerrena [4.2K]

Solving an equation means finding a value of a variable that make the equation true. This value is called the solution of the equation.<span> A mathematical equation is just like a balanced equation. Both sides of the equation should be equal at all times. </span><span>Whatever we do to one side, has to be done on the opposite side.</span>

$9|4p + 2| + 8 = 35$

$
9|4p+2|=35-8
 
$ $Subtract \ 8 \ from \ both \ sides$

$9|4p+2|=27

 
$

$|4p+2|= \dfrac{27}{9}$ $Divide \ both \ sides \ by \ 9$

$|4p+2|=3$

$Break \ down \ the \ problem \ into \ these \ 2 \ equations$

$
4p+2=3
 
$

$-(4p+2)=3$

$Solve \ the \ 1st \ equation: \ 4p+2=3$

$4p=3-2$   <span> $Subtract \ 2 \ from \ both \ sides$
</span>
$4p=1$

$p= \dfrac{1}{4}$   <span> $Divide \ both \ sides \ by \ 4$
</span>
$Solve \ the \ 2nd \ equation: \ -(4p+2)=3$

$-4p−2=3$    $Simplify \ brackets$

$-4p=3+2$ <span> $Add \ 2 \ to \ both \ sides$
</span>
$-4p=5$

$p= -\dfrac{5}{4}$

$Collect \ all \ solutions$

$p= -\dfrac{5}{4}$ , $p= \dfrac{1}{4}$

8 0

3 years ago