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pishuonlain [190]
1 year ago
10

Find the measures of angles of triangle DEF

Mathematics
2 answers:
Alchen [17]1 year ago
8 0

Answer:

<h3>Angle E = 90° </h3><h3>Angle D= 55° </h3><h3>Angle F = 35° </h3>

Sum of all the angles of a triangle = 180° ( angle sum property).

Angle D + Angle E + Angle F = 180°

8x - 1 + 5x + 90° = 180°

8x + 5x + 89 = 180

13x = 180 - 89

13x = 91

x = 7.

Angle D = 8x - 1

= 8(7)-1

= 56 - 1

= 55

Angle E = 90° ( given)

Angle F = 5x

= 5 * 7

= 35

GREYUIT [131]1 year ago
5 0

Answer:

m∠E: 90°

m∠D: 55°

m∠F: 35°

Step-by-step explanation:

Since the interior angles of a right triangle sum up to 180°, the sum of angles D, E, F will equal 180°. We can then form an equation from that information.

90+(8x-1)+5x=180\\13x-1=90\\13x=91\\x=7

From this, we can plug in the variable.

mE=90\\mD=55\\mF=35

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Answer:

A) 34.13%

B)  15.87%

C) 95.44%

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E) 49.87%

F) 0.13%

Step-by-step explanation:

To find the percent of scores that are between 90 and 100, we need to standardize 90 and 100 using the following equation:

z=\frac{x-m}{s}

Where m is the mean and s is the standard deviation. Then, 90 and 100 are equal to:

z=\frac{90-100}{10}=-1\\ z=\frac{100-100}{10}=0

So, the percent of scores that are between 90 and 100 can be calculated using the normal standard table as:

P( 90 < x < 100) = P(-1 < z < 0) = P(z < 0) - P(z < -1)

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It means that the PERCENT of scores that are between 90 and 100 is 34.13%

At the same way, we can calculated the percentages of B, C, D, E and F as:

B) Over 110

P( x > 110 ) = P( z>\frac{110-100}{10})=P(z>1) = 0.1587

C) Between 80 and 120

P( 80

D) less than 80

P( x < 80 ) = P( z

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P( 70

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3 years ago
Combine like terms 1,17-0,07a+(-3,92a).<br><br> HELPPPPPPP!!!
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Answer:

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Step-by-step explanation:

1.17-0.07a+\left(-3.92a\right)

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Answer:

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Nimfa-mama [501]

Answer:

X= -3;

Y=78

Step-by-step explanation:

A:       X+Y=75

B:       10X+Y=48

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