by the concept of momentum conservation we can say
if net force on a system of mass is ZERO then its momentum will remain conserved
Here a ball is projected upwards so if we take Ball + Earth as a system then total momentum of the system will remain conserved
Initially when ball is on the surface of earth the system has zero momentum and hence we can say after throwing the ball momentum of earth + ball must be zero
now using same equation we can say
given that
from above equation velocity of earth will be
so above will be the recoil speed of earth
Answer:
Acceleration = 311.2 Km/hr²
Explanation:
Given: Radius of the Orbit r= 3.56 × 10⁶ km
Period of the orbit = 28 days = 672 hrs
Sol: We have Fc = MV²/r
⇒M ac = MV²/r
⇒ac = V²/r
First we have to Speed V so for this we have to find the circumference ( distance covered by the moon in one orbit)
⇒ Circumference= 2 π r
= 2 × 3.13149 × 3.56 × 10⁶ km
= 22,368,139.69 Km
Now Speed = Distance /time
Speed = 22,368,139.69 Km / 672 hrs
Speed V = 33,285.92 Km/Hr
Now
ac = V²/r = (33,285.92 Km/hrs)² / 3.56 × 10⁶ km
ac = 311.2 Km/hr²
Answer:
C) 19 m/s
Explanation:
The motion of the cannonball is a projectile motion, which consists of 2 independent motions:
- A uniform motion (constant velocity) along the horizontal direction
- A uniformly accelerated motion (constant acceleration) along the vertical direction
As a result, we have the following:
- The horizontal velocity of the cannonball remains constant during the motion, and it is given by
where
u = 25 m/s is the initial velocity
is the angle
Substituting,
- The vertical velocity keeps changing during the motion due to the acceleration of gravity. However, at the top of the trajectory, the vertical velocity is zero:
This means that at the top of its path, the cannonball has only horizontal velocity, so its velocity is
C) 19 m/s
In this question a lot of information's are provided. Among the information's provided one information and that is the time of 4 seconds is not required for calculating the answer. Only the other information's are required.
Mass of the block that is sliding = 5.00 kg
Distance for which the block slides = 10 meters/second
Then we already know that
Momentum = Mass * Distance travelled
= (5 * 10) Kg m/s
= 50 kg m/s
So the magnitude of the blocks momentum is 50 kg m/s. The correct option among all the given options is option "b".
First the velocity drops to zero in 1.2 secs. In those seconds it went upwards for 7.2 m, then it went from 87.2 to 0m. x-x0=v0*t+1/2*g*t^2 ergo t=sqrt(2x/g) that is 4.1761 s. Finally the total time required is 5.3761 s
