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2 years ago

15

A 9.00 V battery has a 55.0 Ohm

1 answer:

svetoff [14.1K]2 years ago

4 0

Answer:1.47

Explanation:

I got it correct on accelus

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The U.S. Navy has long proposed the construction of extremely low frequency (ELF waves) communications systems; such waves could

Artyom0805 [142]

Answer:

length of a quarter wavelength antenna for transmitter elf waves are zero

Explanation:

Find the length of a quarter wavelength antenna for transmitter elf waves

Given information

frequency (ELF waves) → 77Hz

Speed of light → 3 $\times$ $10^8$ m/s

$v=\lambda f-------------1$

where

$\lambda\\$ → wavelength of the antenna

f → frequency of the ELF waves

$v$ → speed of light

so rewrite the equation in $\lambda$ from

$\lambda=\dfrac{v}{f}$

Substitute $3\times10^8m/s$ = $v$

Substitute 75Hz = f

$\lambda=\dfrac{3\times10^8m/s}{77Hz}$

$=3.9\times 10^6$ m

since we get this value,but this size of antenna mount on submarine is not possible.

so $\lambda$ is zero

6 0

3 years ago

What is the kinetic engery of a baseball five feet above the ground when it has already fallen 32 feet

mylen [45]

The answer is 25 ...

6 0

4 years ago

(TCO-8) A band-pass filter has fC1 = 5 kHz and fC2 = 88 kHz. Calculate Bandwidth (BW) and center frequency (fo) for this filter.

Temka [501]

Bandwidth is the difference between the upper and lower frequencies in a continuous band of frequencies.

Mathematically can be expressed as,

$BW = F_{c2}-F_{c1}$

The upper frequency is 88Hz and the lower frequency is 6, therefore the Bandwidth would be,

$BW = (88-5)kHz$

$BW = 83kHz$

The center frequency is given on the basis of the square root of the multiplication of the two reference frequencies, then,

$f_0 = \sqrt{f_{c1}*f_{c2}}$

$f_0 = \sqrt{88*5}$

$f_0 = 20.97kHz$

7 0

3 years ago

(b) The density of aluminum is 2.70 g/cm3. The thickness of a rectangular sheet of aluminum foil varies

vekshin1

Answer:

(i) $22.48 cm^3$

(ii) $1.5 mm$

Explanation:

Let t be the average thickness of the sheet.

Given that:

Density of the aluminum sheet is $2.70 g/cm^3$

Mass of sheet = 60.7 g

Length of sheet = 50.0 cm

Width of sheet = 30.0 cm

(i) Using, Density=Mass/Volume

$\Rightarrow \text{Volume}=\frac{\text{Mass}}{\text{Density}}$

$\Rightarrow \text{Volume}=\frac{60.7}{2.7}=22.48 cm^3$

Hence, the volume of the sheet is $22.48 cm^3$ .

(ii) Now, as this aluminum sheet is in the shape of a cuboid, so the volume of the sheet is

$\text{Volume}=\text{Length}\times\text{Width}\times\text{Thickness}$

$\Rightarrow 22.48=50\times 30 \times w$

$\Rightarrow w=\frac{22.48}{50\times 30}=0.015 cm$

Hence, the average thickness of the sheet is $1.5 mm$ .

6 0

3 years ago

Sebuah benda berjarak 8 cm di depan cermin cekung yang memiliki fokus 12 cm. perbesaran bayangan yang dihasilkan adalah??

Len [333]

1/s' = 1/f - 1/s
= 1/12 - 1/8
= 2/24 - 3/24
= 2-3/24
= - 1/24
s'= -24
M= |s'/s|
M = |24/8|
M = 3

4 0

3 years ago