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Solnce55 [7]
2 years ago
15

A 9.00 V battery has a 55.0 Ohm

Physics
1 answer:
svetoff [14.1K]2 years ago
4 0

Answer:1.47

Explanation:

I got it correct on accelus

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Answers are ONLY allowed to be ionic, polar covalent, and nonpolar covalent.
Luba_88 [7]
A) It will be 2 covalent bonds
B) covalent bonds occur when there’s 2 atoms that share electrons. In this case by sharing the 2 pairs of valence electrons each atom has a total of 8 valence electrons
8 0
2 years ago
NEEDD SOME HELP ASAP HELP MEHHH<br> 50 pOINTS
Vadim26 [7]
An electron shell can hold 2(n^2) electrons (technically) where n is the shell number, i.e. shell 1 can hold 2, shell 2 can hold 8, 3 holds 18 and so on.
The atomic number of Nitrogen is 7, i.e. it has 7 electrons (to match its 7 protons, assuming it isn't an ion).

With the atomic number, you simply start from shell 1 and work out. So we put 2 electrons in shell 1, leaving us with 5 left. Shell 2 can hold 6 so we can fit all 5 in.

In other words, you should have 2 electron shells on the atom, shell 1 with 2 e- and shell 2 with 5 e-.
3 0
3 years ago
Read 2 more answers
The movement of thermal energy from hot to cold materials is called
Fynjy0 [20]

the answer would be conduction

3 0
3 years ago
Gravitational potential energy is due to....
mote1985 [20]

Answer:

A

Explanation:

I only think its A because of the gravity part...sorry im not good at explaining

5 0
3 years ago
. You have completed your design of a new surgical headlamp. You have decided to power the headlamp using four AA rechargeable b
SSSSS [86.1K]

Answer:

LED run before the batteries are depleted is 3.87 hours

Explanation:

given data

battery = 4 AA

battery is rated = 1.2V, 2550 mAh

power = 3 W

efficient = 95%

to find out

How long will the LED run before the batteries are depleted

solution

we consider here power delivered by battery is = x

so power = x × efficient

3 = x 95%

x = 3.15 W

and

voltage by 4 battery is = 4 × 1.2 = 4.8 V

so current will be = \frac{x}{volatge}

current = \frac{3.15}{4.8}

current = 0.6577 A

so total discharge hours = \frac{2550}{current}

total discharge hours = \frac{2550}{657.7}

time = 3.87 hours

so LED run before the batteries are depleted is 3.87 hours

5 0
3 years ago
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