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Goshia [24]
1 year ago
7

Circle A has center (0, 0) and radius 3. Circle B has center (-5, 0) and radius 1. What sequence of transformations could be use

d to show that Circle A is similar to Circle B?

Mathematics
1 answer:
Dmitrij [34]1 year ago
8 0

A translation of T(x, y) = (- 5, 2) and a dilation with center (- 5, 2) with a scale factor of 1 / 3 are necessary to transform circle A into circle B. (Correct choice: D)

<h3>What sequence of rigid transformations can be done on a circle</h3>

In this problem we must determine the sequence of transformations require to transform circle A into circle B. From analytical geometry we know that the equation of the circle in standard form is:

(x - h)² + (y - k)² = r²

Where:

  • (h, k) - Coordinates of the center.
  • r - Radius of the circle.

Then, we need to apply the following rigid transformations:

Translation

f(x, y) → f(x - h, y - k), where (h, k) is the translation vector.

Dilation with center at the center of the circle

r → k · r, where k is the scale factor.

The circle A is represented by x² + y² = 3, then we derive the expression for the circle B:

f(x, y) → f(x + 5, y - 2)

(x + 5)² + (y - 2)² = 9

r → k · r

(x + 5)² + (y - 2)² = (1 / 3)² · 9

(x + 5)² + (y - 2)² = 1

Then, a translation of T(x, y) = (- 5, 2) and a dilation with center (- 5, 2) are necessary to transform circle A into circle B.

To learn more on rigid transformations: brainly.com/question/28004150

#SPJ1

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Answer:

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Step-by-step explanation:

This question is asking you to use and make an equation using the base of the "point-slope form." This is a common equation used when dealing with coordinates and graphs in math. The point-slope form equation looks like this:

y - y₁ = m(x - x₁).

We are going to need to use this equation base to create our problem from the information given. If you are wondering what those subscripts of 1 mean (the 1 in y₁ and x₁), I will explain. Remember that:

slope (m) = <u>y - y₁</u>

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So, our first y value (which is the y-coordinate of 5 in [-3, 5]) can be added into the problem base that I had mentioned above:

y - <u>5</u> = m(x - x₁).

Now, we need to place the first x value (which is the -3 in [-3, 5]) can be added into the base problem once more:

y - 5 = m(x - (<u>-3</u>)).

Because a negative number with a negative symbol in front of it creates a positive, we can change that as well:

y - 5 = m(x + 3).

Fortunately, the question provides a slope ready for use. The question says that the slope is -4, so we can place this into the equation now:

y - 5 = -4(x + 3).

I hope that this helps.

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