A pharmacist has 40% and 80% of iodine solutions on hand. How many liters of each iodine solution will be required to produce 4 liters of a 50% iodine mixture?
.
Let x = liters of 40% iodine
then
4-x = liters of 80% iodine
Using algebra:
.40x + .80(4-x) = .50(4)
.40x + 3.20-.80x = 2
3.20-.40x = 2
x = 4 liters (40% iodine)
80% iodine:
4-x = 4-4 = 0 liters needed (80% iodine)
Answer:
y=24
Step-by-step explanation:
Answer:
47550.501
Step-by-step explanation:
I multiplied them all together but i am not sure if i am correct...

18 ÷ 3
= 6/1
Option [a] 6 to 1 is correct !