The <em>estimated</em> displacement of the center of mass of the olive is .
<h3>Procedure - Estimation of the displacement of the center of mass of the olive</h3>
In this question we should apply the definition of center of mass and difference between the coordinates for <em>dynamic</em> () and <em>static</em> conditions () to estimate the displacement of the center of mass of the olive ():
(1)
Where:
- - x-Coordinate of the i-th element of the system, in meters.
- - y-Coordinate of the i-th element of the system, in meters.
- - x-Component of the net force applied on the i-th element, in newtons.
- - y-Component of the net force applied on the i-th element, in newtons.
- - Mass of the i-th element, in kilograms.
- - Gravitational acceleration, in meters per square second.
If we know that , , , , , and , then the displacement of the center of mass of the olive is:
<h3>Dynamic condition
</h3>
<h3>Static condition</h3><h3>
</h3><h3>
</h3><h3 /><h3>Displacement of the center of mass of the olive</h3>
The <em>estimated</em> displacement of the center of mass of the olive is .
To learn more on center of mass, we kindly invite to check this verified question: brainly.com/question/8662931
The engine is 10,000 N I think. Hopefully this helps!!
Total distance covered is 47.1 m whereas displacement is zero.
<h3>Calculation:</h3>
Given,
Diameter, d = 5 m
No. of revolutions = 3
Radius, r = 5/2 = 2.5 m
To find,
Distance =?
Displacement =?
Distance covered in one revolution = 2πr
Put the values in this,
Distance = 2 × 3.14 × 2.5
= 15.7 m
Total distance covered in 3 revolution = 3 × 31.4
= 47.1 m
Displacement is the change in the position of the object or the distance between the initial and final position.
After 3 revolutions the particle comes back to its initial position. Therefore, the displacement is zero.
Hence, the total distance covered in 3 resolutions is 47.1 m whereas displacement is zero.
Learn more about distance and displacement here:
brainly.com/question/3243551
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