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LekaFEV [45]
2 years ago
6

A jogger runs 5.0 km on a straight trail at an angle of 60° south of west. What is the southern component of the run rounded to

the nearest tenth of a kilometer?
A) -4.3 km
B) -2.5 km
C) 2.5 km
D) 4.3 km
Physics
1 answer:
geniusboy [140]2 years ago
5 0

Answer:

4.3 km

Explanation:

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The drop in potential across a resistor in a circuit is 50 V. What is the current
Aleks [24]

Answer: a

Explanation:

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3 years ago
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Question 15
lozanna [386]

Answer:

Time use of cellphone times 3 hours before sleep.

Explanation:

It is scientifically proven that cell-phone use before bed can disturb your sleep. The blue light can cause your brain to release chemicals that associate with staying awake or even waking up. So measure the hours or minutes you use your phone 3 hours before you go to sleep.

8 0
3 years ago
Objects of equal mass are oscillating up and down in simple harmonic motion on two different vertical springs. The spring consta
Zanzabum

Answer:

k_2=920\ N/m

Explanation:

Given that,

The spring constant of spring 1, k_1=230\ N/m

The motion of the object on spring 1 has twice the amplitude as the motion of the object on spring 2, A_1=2A_2

As the magnitude of the maximum velocity is the same in each case, it means the maximum kinetic energy is same in each case. In other words, the total energy is same.

\dfrac{1}{2}k_1A_1^2=\dfrac{1}{2}k_2A_2^2

k_1A_1^2=k_2A_2^2

k_1(2A_2)^2=k_2A_2^2

k_2=920\ N/m

So, the spring constant of spring 2 is 920 N/m. Hence, this is the required solution.

3 0
3 years ago
A mountain climber increases their height from 200 meters to 400 meters. What affect will this have on their potential energy?
Yanka [14]

Answer:

At 400 m the potential energy of the mountain climber doubled the initial value.

Explanation:

Given;

initial height of the mountain climber = 200 m

final height of the mountain climber, = 400 m

The potential energy of the mountain climber is calculated as;

Potential energy, P.E = mgh

At 200 m, P.E₁ = mg x 200 = 200mg

At 400 m, P.E₂ = mg x 400 = 400mg

Then, at 400 m, P.E₂ = 2 x 200mg = 2 x P.E₁

Therefore, at 400 m the potential energy of the mountain climber doubled the initial value.

4 0
3 years ago
To study the properties of various particles, you can accelerate the particles with electric fields. A positron is a particle wi
maria [59]

Answer:

a) a = 5.03x10¹³ m/s²

b) V_{f} = 4.4 \cdot 10^{5} m/s

Explanation:    

a) The acceleration of the positron can be found as follows:

F = q*E    (1)

Also,

F = ma    (2)

By entering equation (1) into (2), we have:

a = \frac{F}{m} = \frac{qE}{m}

<u>Where:</u>

F: is the electric force

m: is the particle's mass = 9.1x10⁻³¹ kg

q: is the charge of the positron = 1.6x10⁻¹⁹ C    

E: is the electric field = 286 N/C

a = \frac{qE}{m} = \frac{1.6 \cdot 10^{-19} C*286 N/C}{9.1 \cdot 10^{-31} kg} = 5.03 \cdot 10^{13} m/s^{2}

b) The positron's speed can be calculated using the following equation:

V_{f} = V_{0} + at

<u>Where</u>:

V_{f}: is the final speed =?

V_{0}: is the initial speed =0

t: is the time = 8.70x10⁻⁹ s

V_{f} = V_{0} + at = 0 + 5.03 \cdot 10^{13} m/s^{2}*8.70 \cdot 10^{-9} s = 4.4 \cdot 10^{5} m/s

I hope it helps you!

4 0
3 years ago
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