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marshall27 [118]
4 years ago
10

A charged capacitor and an inductor are connected in series. At time t = 0, the current is zero, but the capacitor is charged. I

f T is the period of the resulting oscillations, the next time, after t = 0 that the energy stored in the magnetic field of the inductor is a maximum is
Physics
1 answer:
inysia [295]4 years ago
7 0

Answer:

t = T / 2 all energy is stored in the inductor

Explanation:

The circuit described is an oscillating circuit where the charge of the condensation stops the inductor and vice versa, in this system the angular velocity of the oscillation is

          w = √1/LC

          2π / T =√1 / LC

          T = 2π  √LC

The energy is constant and for the initial instant it is completely stored in the capacitor

         Uc = Q₀² / 2C

In the process, the capacitor is discharging and the energy is stored in the inductor until when the charge in the capacitors zero, all the energy is stored in the inductor

        U = L I² / 2

in the intermediate instant the energy is stored in the two elements.

Since the period of the system is T for time t = 0 all energy is stored in the capacitor and for t = T / 2 all energy is stored in the inductor

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how much heat is lost when 71.07g of steam at 100 degrees condenses to form liquid water at 100 degrees
alukav5142 [94]

Answer:

Q = 160.36[kJ], is the heat lost.

Explanation:

This is a thermodynamic problem where we can find the latent heat of vaporization, at a constant temperature of 100 [°C].

We know that for steam at 100[C], the enthalpy is

h_{gas} = 2675.6[kJ/kg]

For liquid water at 100[C], the enthalpy is

h_{water} = 419.17[kJ/kg]

Therefore

h_{g-w} = 2675.6-419.17 = 2256.43[\frac{kJ}{kg} ]

The amout of heat is given by:

Q=h_{g-w}*m\\ where:\\m = mass = 0.07107[kg] = 71.01[g]\\Q = heat [kJ]\\Q =2256.43*0.07107\\Q=160.36[kJ]

3 0
3 years ago
Whta is the mechanical advantage when the effort force is 20 and the resistance force is 5
pogonyaev
The mechanical advantage would be 4. 20/5=4
7 0
3 years ago
Consider the cylindrical weir of diameter 3 m and length 6m. If the fluid on the left has a specific gravity of 0.8, find the ma
sladkih [1.3K]

This question is incomplete, the complete question is;

Consider the cylindrical weir of diameter 3m and length 6m. If the fluid on the left has a specific gravity of 1.6 and on the right has a specific gravity of 0.8, Find the magnitude and direction of the resultant force.

Answer:

- the magnitude of the resultant force is 557.32 kN

- the direction of resultant force is  48.29°

Explanation:

Given the data in the question and the diagram below,

First we work on the force on the left hand side.

Left Horizontal

F_{LH = βgAr

here, h = 3/2 = 1.5 m, β = 1.6, g = 9.81 m/s², A = 3 m × 6 m = 18 m²

we substitute

F_{LH = βgAh = ( 1.6 × 1000 ) × 9.81 × 18 × 1.5 = 423792 N

Left Vertical

F_{LV = ( βgπh² / 2 ) × W

we substitute

F_{LV = [ ( ( 1.6 × 1000 ) × 9.81  × π(1.5)² ) / 2 ] × 6 = 332845.458 N

Now we go to the right hand side

Right Horizontal

F_{RH = βgAh

here, h' = 1.5/2 = 0.75 m, β = 0.8, g = 9.81 m/s², A = 1.5 m × 6 m = 9 m²

we substitute

F_{RH = ( 0.8 × 1000 ) × 9.81 × 9 × 0.75 ) = 52974 N

Right Vertical

F_{RV = ( βgπh² / 4 ) × W

we substitute

F_{RV = [ ( ( 0.8 × 1000 ) × 9.81  × π(1.5)² ) / 4 ] × 6 =  83211.36 N

Hence

Fx = F_{LH - F_{RH = 52974 N - 423792 N =  370818 N

Fy = F_{LV + F_{RV = 332845.458 N + 83211.36 N = 416056.818 N

R = √( Fx² + Fy² ) = √[ (370818 N)² + (416056.818 N)² ] = 557323.3 N

R = 557.32 kN

Therefore, the magnitude of the resultant force is 557.32 kN

Direction of resultant force;

tanθ = Fy / Fx

we substitute

tanθ = 416056.818 N / 370818 N

tanθ = 1.121997

θ = tan⁻¹( 1.121997 )

θ = 48.29°

Therefore, the direction of resultant force is  48.29°

4 0
3 years ago
What do contour lines on a topographic map show? location of game trails lakes and rivers roads and highways elevation of the gr
Lina20 [59]
<span>Contour lines on a topographic map show elevation of the ground. Contour lines on a map that are constructed by connecting points of equal elevation .
</span><span>
</span><span>some general characteristics of contour lines:
</span><span>1) They do not cross each other, split or divide.
</span><span>2) Steep slopes are reprented by contour lines spaced closely. Gentle slopes are reprented by contour lines spaced far apart
</span><span>3) Contour lines trend up valleys and form a "V" or a "U" where they cross a stream.</span>
3 0
3 years ago
How much electrical energy is used by a 350 W television that is operating for
Igoryamba

Answer:

525,000J

Explanation:

Power = work/time

Given

Power = 350 watts

Time = 25 mins = 25 x 60 = 1500 secs

Therefore

350 = work/1500

Cross multiply

Work = 350 x 1500

Work = 525,000J

4 0
3 years ago
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