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marshall27 [118]
4 years ago
10

A charged capacitor and an inductor are connected in series. At time t = 0, the current is zero, but the capacitor is charged. I

f T is the period of the resulting oscillations, the next time, after t = 0 that the energy stored in the magnetic field of the inductor is a maximum is
Physics
1 answer:
inysia [295]4 years ago
7 0

Answer:

t = T / 2 all energy is stored in the inductor

Explanation:

The circuit described is an oscillating circuit where the charge of the condensation stops the inductor and vice versa, in this system the angular velocity of the oscillation is

          w = √1/LC

          2π / T =√1 / LC

          T = 2π  √LC

The energy is constant and for the initial instant it is completely stored in the capacitor

         Uc = Q₀² / 2C

In the process, the capacitor is discharging and the energy is stored in the inductor until when the charge in the capacitors zero, all the energy is stored in the inductor

        U = L I² / 2

in the intermediate instant the energy is stored in the two elements.

Since the period of the system is T for time t = 0 all energy is stored in the capacitor and for t = T / 2 all energy is stored in the inductor

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A tank whose bottom is a mirror is filled with water to a depth of 19.6 cm. A small fish floats motionless a distance of 6.40 cm
ANEK [815]

Answer:

A. 4.82 cm

B. 24.66 cm

Explanation:

The depth of water = 19.6 cm

Distance of fish  = 6.40 cm

Index of refraction of water = 1.33

(A). Now use the below formula to compute the apparent depth.

d_{app} = \frac{n_{air}}{n_{water}} \times d_{real} \\= \frac{1}{1.33} \times 6.40 \\= 4.82 cm.

(B). the depth of the fish in the mirror.

d_{real} = 19.6 cm + (19.6 cm – 6.40 cm) = 32.8 cm

Now find the depth of reflection of the fish in the bottom of the tank.

d_{app} = \frac{n_{air}}{n_{water}} \times d_{real} \\d_{app} = \frac{1}{1.33} \times 32.8  = 24.66\\

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3 years ago
What helps determine how easily magma flows?
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3 years ago
Consider the power dissipated by the two circuits in the video. The ratio of power dissipation in the parallel circuit to that i
rjkz [21]

Answer:

D. 1/9

Explanation:

Firstly, draw the circuits, then you solve for resistance in series with the formula- R1 + R2... And in parallel- 1/R1 + 1/R2...

Then after getting your resistance, use the formula for power that relates with resistance and voltage.

This the ratio will be 1/9. The parallel circuit has 1/9 the resistance of the series circuit. Since the potential difference across the two circuits is the same, this implies that the parallel circuit will give out 9 times more power than the series circuit.

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3 years ago
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Bird bones have air pockets in them to reduce their weight. This also gives them an average density significantly less than that
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Answer:

mas of water displaced = 41.4 g

Explanation:

Weight in air = True weight = 45 g

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