for the first one set 3y+y=180 and y+x=180
the second one set w+y=180, 42+x=180, y+20=180, and 87+v
For the first 3 you just have to divide (forget about the square root for now) and then reduce its result by finding two numbers (one of them have to be able to be squared rotted) that multiplied gives the fist result. Then you just have to square root one of the numbers and leave the other one as it is.
For the last 4; you cannot have radicals in the denominator, so you have to multiply both top and bottom by the square root, after that you just reduce.
Hope you understand, if you have any questions please let me know.
Answer:
36 i think
Step-by-step explanation:
Let's start by grouping like terms so we can factor out the most
(4x^4+24x^3)+(12x^2+8x)
now let's factor out as much as possible. we see all coefficients are multiples of 4, we will also factor out as high a degree of x as we can
4x^3(x+6)+4x(3x+2)
now we see that we still have a common multiple of 4x that we can remove
4x(x^2(x+6)+(3x+2))
so we find 4x is the largest value we can factor out
Answer:
It's B: all real numbers greater than 0
Step-by-step explanation:
just did the quiz