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lianna [129]
2 years ago
15

Find the area of a regular 12-sided polygon with side of length s and apothem 8.

Mathematics
2 answers:
aliina [53]2 years ago
5 0
Apothem is the height of a triangel formed by two consecutive vertices with the center.  the are of this triangle = 1/2 s 8  = 4s
there area 12 such triangles in the regular 12 side polygon
So area = 12 * 4 s = 48 s
Alinara [238K]2 years ago
5 0

If\ this\ is\ regular\ 12-sides\ polygon\ it\ is\ build\ from\ 12\ isosceles\\triangles.\\\\
apothem=height\ of\ triangle\\\
side=base\ of\ triangle\\\\
Area\ of\ one\ triangle:\\
A=\frac{s*apothem}{2}=\frac{s*8}{2}=4s\\\\
Area\ of\ polygon\ =12*A=12*4s=48s



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Jessie is 6 years older than Todd, and Todd is 2 years younger than Ryan. If Ryan is r years old, which expression shows how old
mariarad [96]
Jessie = Todd + 6
Todd = Ryan -2

if Ryan = r
so Todd = r-2
then Jessie = (r-2) + 6 = r-4 years old
6 0
3 years ago
What is the solution to this addition sentence? 3/4 + (-1/2) = _____
Vikki [24]

\text{Remove parentheses}\\\frac{3}{4} - \frac{1}{2} \\\text{Simplify}\\\frac{1}{4} \checkmark

6 0
3 years ago
Read 2 more answers
Michael has a set of 24 math problems to do for homework. Michael completed 1/4 of his homework in 3/4 of an hour. If he continu
gtnhenbr [62]

Given:

Total number of problems = 24

Michael completed \dfrac{1}{4} of his homework in \dfrac{3}{4} of an hour.

To find:

What fraction of his homework would he complete in one hour.

Solution:

We have,

Part of work done in \dfrac{3}{4} of an hour =\dfrac{1}{4}

Part of work done in an hour =\dfrac{4}{3}\times \dfrac{1}{4}

                                                =\dfrac{1}{3}

Therefore, he complete \dfrac{1}{3} of his homework in 1 hour. Hence, all options are incorrect.

3 0
2 years ago
Squareroot(y-1) + 3 = y
jek_recluse [69]
Note:xy means x times y and x(y) means the same thing

so
first we get rid of square root then
make the equation equal to zero becaues if
xy=0 then x or/and y=0



squareroot(y-1)+3=y

isolate the squareroot
subtrac 3 from boht sides

squareroot(y-1)=y-3

square both sides (since they are equal, you should be able to square both sides and still make it true)

(squareroot(y-1))^2=(y-3)^2
(y-1)=(y-3)(y-3)
y-1=y^2-6y+9
subtrac y from both sides
-1=y^2-7y+9
add 1 to both sides
0=y^2-7y+10
find what two number multiply to make 10 and add to get -7
the answer is -2 and -5

0=(y-5)(y-2)
therfore
y-5=0
and/or
y-2=0

therefor
y=5 or/and 2 might work
let's try out 2
square root(2-1)+3=2
square root(1)+3=2
1+3=2
false
so 2 doesn't work



let's try 5
squareroot(5-1)+3=5
squareroot(4)+3=5
2+3=5
5=5
true

y=5
7 0
3 years ago
I need to find the area
SCORPION-xisa [38]

Answer: 24 sq. ft

Step-by-step explanation: 20 x 36 - (36 - 20 / 2 ) x (20 - 14 )= 24 sq. ft

4 0
2 years ago
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