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Sav [38]
3 years ago
7

The graph of a function increases twice as much over each subsequent equally sized interval. Which of the following could be the

parent function of the graphed function?

Mathematics
2 answers:
Iteru [2.4K]3 years ago
8 0
I hope this helps you





square root of (4x+41)=x+5



4x+41>=0



x >= -10.25



(square root of4x+41)^2=(x+5)^2




4x+41=x^2+10x+25



x^2+6x-16 =0



x +8



x -2



(x+8)(x-2)=0




x= -8



x= 2 extraneous
VikaD [51]3 years ago
7 0

Answer:

The correct option is 1.

Step-by-step explanation:

The given equation is

\sqrt{4x+41}=x+5

Taking square on both the sides.

4x+41=(x+5)^2

4x+41=x^2+10x+25              [\because (a+b)^2=a^2+2ab+b^2]

0=x^2+10x+25-4x-41

0=x^2+6x-16

0=x^2+8x-2x-16

0=x(x+8)-2(x+8)

0=(x+8)(x-2)

x=2,-8

Check the equation by x=2.

\sqrt{4(2)+41}=2+5

\sqrt{49}=7

7=7

LHS=RHS, therefore x=2 is not an extraneous solution.

Check the equation by x=-8.

\sqrt{4(-8)+41}=-8+5

\sqrt{9}=-3

3=-3

LHS≠RHS, therefore x=-8 is an extraneous solution.

Therefore option 1 is correct.

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