2 years ago

Find the area of an equilateral triangle (regular 3-gon) with 6-inch sides. Round your answer to the nearest hundredth.

1 answer:

7 0

Area=9ROOT3 inches
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nasty-shy [4]

Answer:

$A * B = \left[\begin{array}{ccc}10&-6\\8&5\\19&-10\end{array}\right]$

Step-by-step explanation:

Given

$A =\left[\begin{array}{cc}2&-2\\3&4\\4&-3\end{array}\right]$

$B = \left[\begin{array}{cc}4&-1\\-1&2\end{array}\right]$

Required

$AB$

To do this, we simply multiply the rows of A by the column of B;

So, we have:

$A * B = \left[\begin{array}{ccc}2*4 + -2*-1&2*-1+-2*2\\3*4+4*-1&3*-1+4*2\\4*4-3*-1&4*-1-3*2\end{array}\right]$

$A * B = \left[\begin{array}{ccc}10&-6\\8&5\\19&-10\end{array}\right]$

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2 years ago