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Leno4ka [110]
3 years ago
15

Jackson drove 1,080 miles in 20 hours. What was his speed in miles per hour?

Mathematics
1 answer:
Darina [25.2K]3 years ago
4 0

Answer:

54mph

Step-by-step explanation:

To find the speed in "miles per hour" or miles/hour, divide the number of miles by number of hours.

1080 miles/20 hours

= 54miles/hour

His speed is 54 miles per hour.

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Pre-Calculus - Systems of Equations with 3 Variables please show work/steps
inessss [21]

Answer:

x = 10 , y = -7 , z = 1

Step-by-step explanation:

Solve the following system:

{x - 3 z = 7 | (equation 1)

2 x + y - 2 z = 11 | (equation 2)

-x - 2 y + 9 z = 13 | (equation 3)

Swap equation 1 with equation 2:

{2 x + y - 2 z = 11 | (equation 1)

x + 0 y - 3 z = 7 | (equation 2)

-x - 2 y + 9 z = 13 | (equation 3)

Subtract 1/2 × (equation 1) from equation 2:

{2 x + y - 2 z = 11 | (equation 1)

0 x - y/2 - 2 z = 3/2 | (equation 2)

-x - 2 y + 9 z = 13 | (equation 3)

Multiply equation 2 by 2:

{2 x + y - 2 z = 11 | (equation 1)

0 x - y - 4 z = 3 | (equation 2)

-x - 2 y + 9 z = 13 | (equation 3)

Add 1/2 × (equation 1) to equation 3:

{2 x + y - 2 z = 11 | (equation 1)

0 x - y - 4 z = 3 | (equation 2)

0 x - (3 y)/2 + 8 z = 37/2 | (equation 3)

Multiply equation 3 by 2:

{2 x + y - 2 z = 11 | (equation 1)

0 x - y - 4 z = 3 | (equation 2)

0 x - 3 y + 16 z = 37 | (equation 3)

Swap equation 2 with equation 3:

{2 x + y - 2 z = 11 | (equation 1)

0 x - 3 y + 16 z = 37 | (equation 2)

0 x - y - 4 z = 3 | (equation 3)

Subtract 1/3 × (equation 2) from equation 3:

{2 x + y - 2 z = 11 | (equation 1)

0 x - 3 y + 16 z = 37 | (equation 2)

0 x+0 y - (28 z)/3 = (-28)/3 | (equation 3)

Multiply equation 3 by -3/28:

{2 x + y - 2 z = 11 | (equation 1)

0 x - 3 y + 16 z = 37 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract 16 × (equation 3) from equation 2:

{2 x + y - 2 z = 11 | (equation 1)

0 x - 3 y+0 z = 21 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Divide equation 2 by -3:

{2 x + y - 2 z = 11 | (equation 1)

0 x+y+0 z = -7 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract equation 2 from equation 1:

{2 x + 0 y - 2 z = 18 | (equation 1)

0 x+y+0 z = -7 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Add 2 × (equation 3) to equation 1:

{2 x+0 y+0 z = 20 | (equation 1)

0 x+y+0 z = -7 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Divide equation 1 by 2:

{x+0 y+0 z = 10 | (equation 1)

0 x+y+0 z = -7 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Collect results:

Answer: {x = 10 , y = -7 , z = 1

3 0
3 years ago
Me Help ASAP or when everrr
Ierofanga [76]

Answer:

Base = 3√5

Step-by-step explanation:

Given:

Hypotenuse = 9

Perpendicular = 6

Find:

Base(x)

Computation:

Using Pythagorean theorem

Base = √Hypotenuse² - Perpendicular²

Base = √9² - 6²

Base = √81 - 36

Base = √45

Base = 3√5

8 0
3 years ago
The workers at Cameron's Flower shop are putting 1,323 flowers into vases for a party .Each base must hold exactly 8 flowers .Wh
Alika [10]

Answer:

165

Step-by-step explanation:

How many complete vases can Cameron's Flower shop fill with 8 flowers each, considering they have a total of 1,323 flowers in total.

All you have to do is divide 1,323 by 8 to get = 165.375 or 165 and 3/8.

Since the question is about COMPLETE vases of 8 flowers, that means the answer is 165, and we don't count the 3 remaining flowers.

Good job Cameron!

3 0
3 years ago
Read 2 more answers
True or false: Every kite is a rhombus, but not every rhombus is a kite.
horsena [70]

This is false. Kites can be shaped in many different ways so not all kites are rhombuses. Also, even the kites that look like rhombuses may not be rhombuses. Most kites have 2 pairs of sides with the same length. But, in order to be a rhombus all the sides have to be the same length but not all sides are the same length on a typical kite.

7 0
3 years ago
Two points in the xy plane have cartesian coordinates (1.50, −3.00) m and (−7.50, 7.50) m. (a) determine the distance between th
vova2212 [387]
Distance  = sqrt [ (7.5 - -3.0)^2 + (-7.5 - .5)^2) ]

                = sqrt 17,226.56  =  131.25 (answer)
3 0
3 years ago
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