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3 years ago

A statistical study reported that a drug was effective with a p-value of .042.

Mathematics

1 answer:

loris [4]3 years ago

5 0

Answer:

(a) An ineffective sample may be found about 42 times in 1000 samples.

(b) Yes, the drug is evidently effective at alpha = 0.05.

(c) A drug that had a p-value of 0.042 is more effective in comparison to a drug that had a p-value of 0.087.

Step-by-step explanation:

We are given that a statistical study reported that a drug was effective with a p-value of 0.042.

Let the Null Hypothesis, $H_0$ : The drug was ineffective.

Alternate Hypothesis, $H_A$ : The drug was effective.

(a) An ineffective sample may be found about 42 times in 1000 samples.

(b) As we know that, if the P-value is less than the level of significance, then we have sufficient evidence to reject our null hypothesis.

SO, here also; the P-value is less than the level of significance as 0.042 < 0.05, so we reject our null hypothesis and conclude that the drug is evidently effective.

(c) The drug that had a p-value of 0.087 would be ineffective as in this case the P-value is more than the level of significance as 0.087 > 0.05, so we do not reject our null hypothesis and conclude that the drug is evidently ineffective.

This means that a drug that had a p-value of 0.042 is more effective in comparison to a drug that had a p-value of 0.087.

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4 years ago

1/5 (4-3x) = 1/7 (3x - 4) pls solve

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$\huge \boxed{\mathfrak{Question} \downarrow}$

$\large\sf\frac{1}{5} (4 - 3x) = \frac{1}{7} (3x - 4) \\$

$\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}$

$\frac{1}{5} (4 - 3x) = \frac{1}{7} (3x - 4) \\$

Use the distributive property to multiply 1/5 by 4-3x.

$\frac{1}{5}\times 4+\frac{1}{5}\left(-3\right)x=\frac{1}{7}\left(3x-4\right) \\$

Multiply 1/5 and 4 to get 4/5.

$\frac{4}{5}+\frac{1}{5}\left(-3\right)x=\frac{1}{7}\left(3x-4\right) \\$

Multiply 1/5 and -3 to get -3/5.

$\frac{4}{5}+\frac{-3}{5}x=\frac{1}{7}\left(3x-4\right) \\$

Use the distributive property to multiply 1/7 by 3x-4.

$\frac{4}{5}-\frac{3}{5}x=\frac{1}{7}\times 3x+\frac{1}{7}\left(-4\right) \\$

Multiply 1/7 and 3 to get 3/7 & 1/7 × -4 to get -4/7.

$\frac{4}{5}-\frac{3}{5}x=\frac{3}{7}x-\frac{4}{7} \\$

Subtract $\frac{3}{7}x\\$ from both sides.

$\frac{4}{5}-\frac{3}{5}x-\frac{3}{7}x=-\frac{4}{7} \\$

Combine $-\frac{3}{5}x\\$ and $-\frac{3}{7}x\\$ to get $-\frac{36}{35}x\\$ .

$\frac{4}{5}-\frac{36}{35}x=-\frac{4}{7} \\$

Subtract 4/5 from both sides.

$-\frac{36}{35}x=-\frac{4}{7}-\frac{4}{5} \\$

The least common multiple of 7 and 5 is 35. Convert -4/7 and 4/5 to fractions with denominator 35.

$-\frac{36}{35}x=-\frac{20}{35}-\frac{28}{35} \\$

Because $-\frac{20}{35} \\$ and $\frac{28}{35}\\$ have the same denominator, subtract them by subtracting their numerators.

$-\frac{36}{35}x=\frac{-20-28}{35} \\$

Subtract 28 from -20 to get -48.

$-\frac{36}{35}x=-\frac{48}{35} \\$

Multiply both sides by $-\frac{35}{36}\\$ , the reciprocal of $-\frac{36}{35}\\$ .

$x=-\frac{48}{35}\left(-\frac{35}{36}\right) \\$

Multiply $-\frac{48}{35}\\$ by $-\frac{35}{36}\\$ by multiplying the numerator by the numerator and the denominator by the denominator.

$x=\frac{-48\left(-35\right)}{35\times 36} \\$

Carry out the multiplications in the fraction $\frac{-48\left(-35\right)}{35\times 36}\\$ .

$x=\frac{1680}{1260} \\$

Reduce the fraction 1680/1260 to its lowest terms by extracting and cancelling out 420.

$\huge \boxed{ \boxed{ \bf \: x=\frac{4}{3} \approx \: 1.33}}$

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