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3 years ago

Find the mean for the following set o of data 16, 45 35, 39, 22, 23

Mathematics

2 answers:

Leto [7]3 years ago

6 0

The mean is 23 because it is the middle number

Pepsi [2]3 years ago

4 0

23 is the answer because it is in the middle

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Seth's father is thinking of buying his son a summer movie pass for $30 dollars. With the pass, matiness cost $4 each.

PilotLPTM [1.2K]

Answer:

Seth saved $90.

Step-by-step explanation:

1.Find out how much would be spent without buying the movie pass.

Multiply the amount of money that one would spend for each movie, by the number of movies one saw.

8 * 30 = 240

2.Find out the amount that was actually spent

Multiply the amount that was actually spent on each movie, by the number of movies that were seen. Then add the additional cost of the pass.

(4 * 30) + 30

= 120 + 30

= 150

3. Find the difference between the two values.

Subtract the amount that one was supposed to spend by the amount one did spend.

240 - 150

= 90

3 0

3 years ago

I need help with this someone please

Alex

3/1 is your slope for that

7 0

3 years ago

find two consecutive odd numbers such that the sum of the larger number and twice the smaller number is 27 less than four times

Vlad1618 [11]

Answer:

DANG some of these questions are from like 2017 and still havent been answerd

Step-by-step explanation:

7 0

3 years ago

Complete the square to rewrite x^2+y^2+2x+6y-6=0 in graphing form

Ksivusya [100]

Answer:

(x + 1)² + (y + 3)² = 16

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

Given

x² + y² + 2x + 6y - 6 = 0

Collect the x and y terms together and add 6 to both sides

x² + 2x + y² + 6y = 6

To complete the square

add ( half the coefficient of the x/ y terms )² to both sides

x² + 2(1)x + 1 + y² + 2(3)y + 9 = 6 + 1 + 9

(x + 1)² + (y + 3)² = 16

with centre = (- 1, - 3) and r = $\sqrt{16}$ = 4

4 0

3 years ago

Coach Evans recorded the height, in inches of each player on his team. The results are shown.

marysya [2.9K]

Answer:

Step-by-step explanation:

Given:

Team heights (inches):

61, 57, 63, 62, 60, 64, 60, 62, 63

To find: IQRs (interquartile ranges) of the heights for the team

Solution:

A quartile divides the number of terms in the data into four more or less equal parts that is quarters.

For a set of data, a number for which 25% of the data is less than that number is known as the first quartile $(Q_1)$

For a set of data, a number for which 75% of the data is less than that number is known as the third quartile $(Q_3)$

Terms in arranged in ascending order:

$57,60,60,61,62,62,63,63,64$

Number of terms = 9

As number of terms is odd, exclude the middle term that is 62.

$Q_1$ is median of terms $57,60,60,61$

Number of terms (n) = 4

Median = $\frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th} }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{60+60}{2}=\frac{120}{2}=60$

So, $Q_1=60$

So, 25% of the heights of a team is less than 60 inches

$Q_3$ is the median of terms $62,63,63,64$

Median = $\frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th} }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{63+63}{2}=\frac{126}{2}=63$

So, $Q_3=63$

So, 75% of the heights of a team is less than 63 inches

Interquartile range = $Q_3-Q_1=63-60=3$

The interquartile range is a measure of variability on dividing a data set into quartiles.

The interquartile range is the range of the middle 50% of the terms in the data.

So, 3 is the range of the middle 50% of the heights of the students.

4 0

3 years ago