Solve for x.<br> a = bx<br> A) (-b)\a<br> B) b - a<br> C) (-a) + b<br> D) (-a)/b

Please show me how you got the answer. Will give brainliest.

umka21 [38]

Answer: 410 possible points

To solve for the possible points in the course, use a proportion and cross multiply.

<h2>What is a proportion?</h2>

A proportion is two fractions that are equal to each other. For the fractions to be equal, they are proportionate. In our math problem, percentage is proportionate the the number of points.

The fractions represent information you have, and one variable will represent what you are solving for.

<h2 /><h3>Given</h3>

Your points = 361

Points to get an 'A' = your points + 8

'A' = 90% of possible points

<h3>Find the points needed for an 'A' at 90%</h3>

Points to get an 'A' = your points + 8

= 361 + 8

= 369

<h3>State variables</h3>

let <em>x</em> be the amount of possible points

<h3 /><h3>Write a proportion</h3>

We know the number of points for 90% is 369 points. Remember that 90% is the same as 90/100.

Keep the information with the same units inside the same fraction. Here, percentage is represented by the first fraction. Points is represented by the second fraction.

$\displaystyle{\frac{90}{100}=\frac{369}{x}}$

<h3>Solve</h3>

We can solve using cross multiplication. This is when we multiply each numerator by the denominator from the other fraction.

$90x = 369*100$ Simplify by multiplying.

$90x = 36,900$ Isolate the variable <em>x</em>.

$\displaystyle{\frac{90x}{90} = \frac{36,900}{90}}$ Divide both sides by 90 to cancel out 90 on the left.

$\displaystyle{x = \frac{36,900}{90}}$ Divide.

$x = 410$ Solved for <em>x</em>, representing the possible points.

∴ The possible points in the art course is 410.

Learn more about finding a missing number given percentage here: brainly.com/question/26535441

4 0

1 year ago

There are 5 red marbles, 8 blue marbles, and 12 green marbles in a bag. What is the theoretical probability of randomly drawing

zheka24 [161]

25 total marbles, 17 red plus green, so id say d) 68%

7 0

2 years ago

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Which auto insurance coverage pays for injury or damage that the insured driver causes to other people or their property?

pashok25 [27]

Bodily injury liability and property damage liability is the auto insurance coverage that pays for injury or damage that the insured driver causes to other people or their property

To add, bodily injury liability also provides a legal defense in the event that you are sued for damages. Also, property damage liability<span> <span>coverage helps pay for the </span></span>damage<span> <span>that you cause to another vehicle, or other types of </span></span>property<span>.<span> </span></span>

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3 years ago

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What is the answer to this 4×3^2?<br><br>Evaluate the expression.

Neporo4naja [7]

The answer to this question is 36

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3 years ago

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The heights of a random sample of 50 college students showed a mean of 174.5 centimeters and a standard deviation of 6.9 centime

Minchanka [31]

Answer:

Step-by-step explanation:

Hello!

For me, the first step to any statistics exercise is to determine what is the variable of interest and it's distribution.

In this example the variable is:

X: height of a college student. (cm)

There is no information about the variable distribution. To estimate the population mean you need a variable with at least a normal distribution since the mean is a parameter of it.

The option you have is to apply the Central Limit Theorem.

The central limit theorem states that if you have a population with probability function f(X;μ,δ²) from which a random sample of size n is selected. Then the distribution of the sample mean tends to the normal distribution with mean μ and variance δ²/n when the sample size tends to infinity.

As a rule, a sample of size greater than or equal to 30 is considered sufficient to apply the theorem and use the approximation.

The sample size in this exercise is n=50 so we can apply the theorem and approximate the distribution of the sample mean to normal:

X[bar]~~N(μ;σ2/n)

Thanks to this approximation you can use an approximation of the standard normal to calculate the confidence interval:

98% CI

1 - α: 0.98

⇒α: 0.02

α/2: 0.01

$Z_{1-\alpha /2}= Z_{1-0.01}= Z_{0.99} =2.334$

X[bar] ± $Z_{1-\alpha /2} * \frac{S}{\sqrt{n} }$

174.5 ± $2.334* \frac{6.9}{\sqrt{50} }$

[172.22; 176.78]

With a confidence level of 98%, you'd expect that the true average height of college students will be contained in the interval [172.22; 176.78].

I hope it helps!

4 0

3 years ago

Solve for x. ­a = bx A) (­-b)\a B) b -­ a C) (­-a) + b D) (­-a)/b

Solve for x. a = bx A) (-b)\a B) b - a C) (-a) + b D) (-a)/b