Might have to experiment a bit to choose the right answer.
In A, the first term is 456 and the common difference is 10. Each time we have a new term, the next one is the same except that 10 is added.
Suppose n were 1000. Then we'd have 456 + (1000)(10) = 10456
In B, the first term is 5 and the common ratio is 3. From 5 we get 15 by mult. 5 by 3. Similarly, from 135 we get 405 by mult. 135 by 3. This is a geom. series with first term 5 and common ratio 3. a_n = a_0*(3)^(n-1).
So if n were to reach 1000, the 1000th term would be 5*3^999, which is a very large number, certainly more than the 10456 you'd reach in A, above.
Can you now examine C and D in the same manner, and then choose the greatest final value? Safe to continue using n = 1000.
Answer:
72
Step-by-step explanation:
(24*6)/2 = 72
48.00 is the answer your looking for
Answer:
The Answer is C, because -4 is 4 units away from 0
Step-by-step explanation:
The signs | | tells us directly how far a number is from zero. This is represented by said number
A)
Let c be the number of right guesses.
the probability of c answers =.25 and probability of the wrong answer is 1-.25=.75
c distribution is in the parameter of (20, .25).
b) mean = 20 * .25== 5
c) p of c guess =.25 ^20 =9.095* 10 ^-13
d) p of 10 c guess =.014 or 1.4% it is not possible for him to have 10 right guess.
