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3 years ago

A rectangle has length 7 inches and width 3 inches.

Mathematics

1 answer:

Naya [18.7K]3 years ago

6 0

Answer:

The area of rectangle is 21 in^2

Step-by-step explanation:

we know that

The area of rectangle is equal to

$A=LW$

where

L is the length

W is the width

In this problem we have

$L=7\ in$

$W=3\ in$

substitute

$A=(7)(3)=21\ in^2$

The draw in the attached figure

therefore

The area of rectangle is 21 in^2

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Write an equation in point-slope form of the line that passes through the points

Aleksandr-060686 [28]

Hello!

Step-by-step explanation:

Slope: $\frac{Y^2-Y^1}{X^2-X^1}=\frac{rise}{run}$

$\frac{(-2)-(-4)=-2+4=2}{3-2=1}=\frac{2}{1}=2$

Answer: 2

Slope is 2.

Hope this helps!

Thanks!

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Have a great day!

4 0

3 years ago

6. a. Sixty students in a class took an examination in Physics and Mathematics. If 17 of them passed Physics only, 25 passed in

Ivahew [28]

Let $C$ be the set of all students in the classroom.

Let $P$ and $M$ be the sets of students that pass physics and math, respectively.

We're given

$n(C) = 60$

$n(P \cap M') = 17$

$n(P \cap M) = 25$

$n((P \cup M)') = n(P' \cap M') = 9$

i. We can split up $P$ into subsets of students that pass both physics and math $(P\cap M)$ and those that pass only physics $(P\cap M')$ . These sets are disjoint, so

$n(P) = n(P\cap M) + n(P\cap M') = 25 + 17 = \boxed{42}$

ii. 9 students fails both subjects, so we find

$n(C) = n(P\cup M) + n(P\cup M)' \implies n(P\cup M) = 60 - 9 = 51$

By the inclusion/exclusion principle,

$n(P\cup M) = n(P) + n(M) - n(P\cap M)$

Using the result from part (i), we have

$n(M) = 51 - 42 + 25 = 34$

and so the probability of selecting a student from this set is

$\mathrm{Pr}(M) = \dfrac{34}{60} = \boxed{\dfrac{17}{30}}$

7 0

2 years ago

Yesterday, Caitlin swam 20 laps in the pool. Hannah swam 4/5 as many laps As Caitlin. How many laps did Hannah swim?

Misha Larkins [42]

Caitlin = 20 laps

Hannah = 4/5 as many laps

Multiply the laps swan by Caitlin (20) by 4/5

20 x 4/5 = 80/5 = 16

Hannah swam 16 laps

6 0

1 year ago

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shtirl [24]

Answer:

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The domain of the inverse of a relation is the same as the range of the original relation. In other words, the y-values of the relation are the x-values of the inverse.

Thus, domain of f(x): x∈R = range of f¯¹(x)

and range of f(x): x∈R =domain of f¯¹(x)

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2 years ago

Pleasantburg has a population growth model of P(t)=at2+bt+P0 where P0 is the initial population. Suppose that the future populat

yulyashka [42]

Answer:

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