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snow_tiger [21]
4 years ago
9

Titanium dioxide, TiO₂, reacts with carbon and chlorine to give gaseous TiCl₄: TiO₂+2C+2CI₂−TiCI₄+2CO The reaction of 7.39 kg ti

tanium dioxide with excess C and Cl₂ gives 14.24 kg titanium tetrachloride. Calculate the theoretical yield of TiCl₄ (assuming complete reaction) and its percentage yield.
Chemistry
1 answer:
Dima020 [189]4 years ago
3 0

Answer:

17.57kg of TiCl_{4} and its percentage yield is 81.0%

Explanation:

Through the reaction you can get the theoretical amount of  TiCl_{4} that must be produced.

7.39kgTiO_{2}x\frac{1kmolTiO_{2} }{79.867kgTiO_{2}}x \frac{1kmolTiCl_{4}}{1kmolTiO_{2}}x\frac{189.867kgTiCl_{4} }{1kmolTiCl_{4}}=17.57kgTiCl_{4}

If the amount obtained is less than the theoretical amount, it means that the initial sample was not 100% pure. Now the actual amount obtained is compared with the theoretical amount using a percentage

yield=\frac{actual amount}{theoretical amount}x100= \frac{14.24kg}{17.57kg}x100=81.0%

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C_xH_yO_z+O_2\rightarrow CO_2+H_2O

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We are given:

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In 44g of carbon dioxide, 12 g of carbon is contained.

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For calculating the mass of hydrogen:

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Mass of oxygen in the compound = (5.287) - (3.338+0.278) = 1.671  g

Step 1 : convert given masses into moles.

Moles of C =\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{3.338g}{12g/mole}=0.278moles

Moles of H=\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{0.278g}{1g/mole}=0.278moles

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Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

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For H =\frac{0.278}{0.104}=3

For O =\frac{0.104}{0.104}=1

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