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Bezzdna [24]
3 years ago
8

If you repeat the perpendicular line segment construction twice using paper folding, you can construct:

Mathematics
2 answers:
Amanda [17]3 years ago
7 0
D.is the correct answer
Leni [432]3 years ago
7 0

Answer with explanation:

→→ Take a Rectangular piece of Paper.Draw a line segment anywhere on the piece of Paper.Fold the Paper from side adjacent to line segment.You will get line segment perpendicular to line segment.

→→In this process you will get two congruent angles each being equal to 90°.As well as you will get a pair of Parallel lines.

So, we can Construct

Option (B)→An angle congruent to a given angle.

Option (C)→A parallel to a line through a point not on the line.

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What is the value of the expression below when y=7?<br><br><br> y2+5y+6
Daniel [21]

Answer:

90

Step-by-step explanation:

y^2 + 5y + 6 =

(7)^2 + 5(7) + 6 =

49 + 35 + 6 =

84 + 6 =

90

5 0
2 years ago
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Students are making ornaments and each takes 1/4 of a piece of Bristol board. They go to the cupboard and find 2 1/2 pieces of B
coldgirl [10]

Answer: 10 ornaments

Step-by-step explanation:

From the question, we are informed that students are making ornaments and each takes 1/4 of a piece of Bristol board. We are further told that they go to the cupboard and find 2 1/2 pieces of Bristol board.

The number of ornaments that they make will be gotten by dividing 2 1/2 by 1/4. This will be:

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= 5/2 ÷ 1/4

= 5/2 × 4/1

= 10

They can make 10 ornaments

5 0
2 years ago
What is rounding and estimate 253,495 - 48,617=
fomenos
Rounding up or down to the nearest whole number, 253,000-49,000=204,000
4 0
2 years ago
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Please answer this math question please and fast
lions [1.4K]

Answer:

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Step-by-step explanation:

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Which expression is equivalent to StartFraction (5 a b) cubed Over 30 a Superscript negative 6 Baseline b Superscript negative 7
m_a_m_a [10]

Answer:

Option D.

Step-by-step explanation:

The given expression is

\dfrac{(5ab)^3}{30a^{-6}b^{-7}}

We need to find the expression, which is equivalent to the given expression.

The given expression can be rewritten as

\dfrac{5^3a^3b^3}{30a^{-6}b^{-7}}     [\because (ab)^m=a^mb^m]

\dfrac{125}{30}\times \dfrac{a^3}{a^{-6}}\times \dfrac{b^3}{b^{-7}}

\dfrac{25}{6}\times a^{3-(-6)}\times b^{3-(-7)}    [\because \dfrac{a^m}{a^n}=a^{m-n}]

\dfrac{25}{6}\times a^{3+6}\times b^{3+7}

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Therefore, the correct option is D.

7 0
3 years ago
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