Answer:
See Explanation
Step-by-step explanation:
8. (1)
Area of trapezoid = 1/2(sum of || sides) *perpendicular distance
36 =1/2(x+ y) * 6
36 = ((x + y)*3
36/3 = x + y
12 = x + y
x + y = 12.... (1)
8(2)
It is given that:
x = 2y....(2)
From equations (1) & (2)
2y + y = 12
3y = 12
y = 12/3
y = 4
From equation (2)
x = 2y = 2*4
x = 8
9.
Area of square = 1 square m
Side of square = 1 m
Area of circle = 1 square m
Answer:
$318
Step-by-step explanation:
6% x 300 = 18
300 + 18 = 318
Answer:
7
Step-by-step explanation:
fdgrgeag
Answer:
78%
Step-by-step explanation:
70 = 0.50 (62) + 0.50 (x)
70 = 31 + 0.5x
39 = 0.5x
x = 78
You must get at least a 78% on the test to have at least 70% in the class.
Answer:
Tn = 2Tn-1 - Tn-2
Step-by-step explanation:
Before we can generate the recursive sequence, we need to find the nth term of the given sequence.
nth term of an AP is given as:
Tn = a+(n-1)d
If a17 = -40
T17 = a+(17-1)d = -40
a+16d = -40 ...(1)
If a28 = -73
T28 = a+(28-1)d = -73
a+27d = -73 ...(2)
Solving both equations simultaneously using elimination method.
Subtracting 1 from 2 we have:
27d - 16d = -73-(-40)
11d = -73+40
11d = -33
d = -3
Substituting d = -3 into 1
a+16(-3) = -40
a - 48 = -40
a = -40+48
a = 8
Given a = 8, d = -3, the nth term of the sequence will be
Tn = 8+(n-1) (-3)
Tn = 8+(-3n+3)
Tn = 8-3n+3
Tn = 11-3n
Given Tn = 11-3n and d = -3
Tn-1 = Tn - d... (3)
Tn-1 = 11-3n +3
Tn-1 = 14-3n
Tn-2 = Tn-2d...(4)
Tn-2 = 11-3n-2(-3)
Tn-2 = 11-3n+6
Tn-2 = 17-3n
From 3, d = Tn - Tn-1
From 4, d = (Tn - Tn-2)/2
Equating both common difference
(Tn - Tn-2)/2 = Tn - Tn-1
Tn - Tn-2 = 2(Tn - Tn-1)
Tn - Tn-2 = 2Tn-2Tn-1
2Tn-Tn = 2Tn-1 - Tn-2
Tn = 2Tn-1 - Tn-2
The recursive formula will be
Tn = 2Tn-1 - Tn-2
