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3 years ago

6

How do I solve number 15?! Plz help!!!!!

1 answer:

Evgesh-ka [11]3 years ago

3 0

first get all variables on the same side, then use elimination to solve.

x = -3

y = -11

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If two angles of a triangle are 10 degrees and 20 degrees, then the triangle is ????

Wewaii [24]

Answer:

Scalene

Step-by-step explanation:

Because all triangular angles add up to 180 degrees.

10+20=30

180-30=150

None of those angles are the same.

5 0

3 years ago

Read 2 more answers

Arrange these numbers from least to greatest: 2 over 5 comma text end text − 3 over 7 comma text end text 2 over 3. A. 2 over 5

liberstina [14]

Given:
Three fractions:
1) 2/5
2) -3/7
3) 2/3

The least is -3/7 because of the negative sign. Second is 2/5, and the greatest is 2/3.

-3/7 is -0.43 in decimal form
2/5 is 0.40 in decimal form
2/3 is 0.67 in decimal form

My answer is:
<span>B. − 3 over 7 comma text end text 2 over 5 comma text end text 2 over 3</span>

3 0

4 years ago

Two particles move in the xy-plane. At time t, the position of particle A is given by x(t)=5t−5 and y(t)=2t−k, and the position

Ipatiy [6.2K]

Answer:

Part A) Not collide

Part B) k = 4

Part C) Particle B is moving fast.

Step-by-step explanation:

Two particles move in the xy-plane. At time, t

<u><em>Position of particle A:-</em></u>

$x(t)=5t-5$

$y(t)=2t-k$

<em><u>Position of particles B:-</u></em>

$x(t)=4t$

$y(t)=t^2-2t+1$

Part A) For k = -6

Position particle A, (5t-5,2t+6)

Position of particle B, $(4t,t^2-2t-1)$

If both collides then x and y coordinate must be same

Therefore,

For x-coordinate:

5t - 5 = 4t

t = 5

For y-coordinate:

$2t+6=t^2-2t-1$

$t^2-4t-7=0$

$t=-1.3,5.3$

The value of t is not same. So, k = -6 A and B will not collide.

Part B) If both collides then x and y coordinate must be same

For x-coordinate:

5t - 5 = 4t

t = 5

For y-coordinate:

$2t-k=t^2-2t-1$

Put t = 5

$10-k=25-10-1$

$k=4$

Hence, if k = 4 then A and B collide.

Part C)

Speed of particle A, $\dfrac{dA}{dt}$

$\dfrac{dA}{dt}=\dfrac{dy}{dt}\cdot \dfrac{dt}{dx}$

$\dfrac{dA}{dt}=2\cdot \dfrac{1}{5}\approx 0.4$

Speed of particle B, $\dfrac{dB}{dt}$

$\dfrac{dB}{dt}=\dfrac{dy}{dt}\cdot \dfrac{dt}{dx}$

$\dfrac{dB}{dt}=2t-2\cdot \dfrac{1}{4}$

At t = 5

$\dfrac{dB}{dt}=10-2\cdot \dfrac{1}{4}=2$

Hence, Particle B moves faster than particle A

8 0

3 years ago

Solve the triangle, AMDM

krok68 [10]

Answer:

B

Step-by-step explanation:

You are given two sides and the included angle, so you need to use the law of cosines.

c² = a² + b² - 2ab cos C

c² = 12² + 13² - 2(12)(13)cos 134°

c² = 313 - 312(-0.6947)

c² = 529.733

c = 23.016

Now use the law of sines.

c/sin C = a/sin A

23.016/sin 134° = 12/sin A

sin A = 12 × sin 134° / 23.016

sin A = 0.37504

A = 22.03°

B = 180° - 134° - 22.03°

B = 23.97°

m<A = 22°; m<B = 24°; c = 23 km

Answer: B

6 0

2 years ago

What is the area of the rhombus?

IRINA_888 [86]

The area of rhombus is 24 square units.

Step-by-step explanation:

Given,

Length of one diagonal = p = 3+3 = 6 units

Length of other diagonal = q = 4+4 = 8 units

Area of rhombus = $\frac{pq}{2}$

Area of rhombus = $\frac{6*8}{2}$

Area of rhombus = $\frac{48}{2}$

Area of rhombus = 24 square units

The area of rhombus is 24 square units.

Keywords: rhombus, area

Learn more about areas at:

#LearnwithBrainly

5 0

3 years ago

Read 2 more answers