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oksano4ka [1.4K]
3 years ago
15

What is the solution to the following equation?

Mathematics
1 answer:
Snowcat [4.5K]3 years ago
5 0

Answer:

A. x=13

Step-by-step explanation:

x + 11 = 24 \\  x = 24 - 11 \\ x = 13

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4 - x + <img src="https://tex.z-dn.net/?f=6%5E%7B2%7D" id="TexFormula1" title="6^{2}" alt="6^{2}" align="absmiddle" class="latex
Lemur [1.5K]

Answer:

x ≤ 19

Step-by-step explanation:

The instructions here are probably "solve for x."  Please include them.

4 - x + 6^2 ≥  21

becomes 4 - x + 36 ≥  21

Now combine like terms.  4 and 36 combine to 40:  40 - x ≥ 21, and so:

19 - x ≥ 0

Adding x to both sies results in

x ≤ 19

Please, include the instructions when you post a question.  Thanks.

3 0
3 years ago
The sum of three consecutive integers if the first is z
valentinak56 [21]
The answer should 1x
3 0
3 years ago
The radius of a cylindrical gift box is ​(4x + 1​) inches. The height of the gift box is three times the radius. What is the sur
user100 [1]

Answer:

S = 128πx² + 64πx + 8π

Step-by-step explanation:

Suraface area of a cylinder is given by:

S = 2πrh + 2πr²

We know that the height is 3 times as big as the radius, hence:

h = 3r

so we can plug in the new h value and rewrite the S equation as:

S = 2πrh + 2πr²

S = 2πr(3r) + 2πr²

S = 6πr² + 2πr²

S = 8πr²

We're given in the question that the radius is ​(4x + 1​) inches, so plug that into r.

Given: r = 4x + 1​

Therefore,

S = 8πr²

S = 8π(4x + 1​)²

S = 8π(16x²+8x+1)

S = 128πx² + 64πx + 8π

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3 years ago
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Irrational numbers

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