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melisa1 [442]
4 years ago
12

When the parameters of a population are known, the likelihood of obtaining a certain mean value, ¯ x , from a small sample can b

e predicted by the z‐variable with z = ( ¯ x − x ' ) / σ / √ N . Consider a stamping process in which the applied load has a known true mean of 400 N with standard deviation of 25 N. If 25 measurements of applied load are taken at random, what is the probability that this sampling will have a mean value between 390 and 410?
Mathematics
1 answer:
spayn [35]4 years ago
6 0

Answer: 0.9545

Step-by-step explanation:

Given : Population mean : x'=400\ N

Standard deviation : \sigma=25\ N

Sample size : n=25

Test statistic : z=\dfrac{\overline{x}-x'}{\dfrac{\sigma}{\sqrt{n}}}

For \overline{x}= 390, we have

z=\dfrac{390-400}{\dfrac{25}{\sqrt{25}}}=-2

For \overline{x}= 410, we have

z=\dfrac{410-400}{\dfrac{25}{\sqrt{25}}}=2

Now, by using the standard normal distribution table for z , we have

\text{P-value=}P(-2

Hence, probability that this sampling will have a mean value between 390 and 410 = 0.9545

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