Answer:
Solving by method of factorization ,
(y^4-y^3+2y^2+y-1)/(y+1)(y^2-y+1)
Step-by-step explanation:
A sum of two perfect cubes, a3 + b3 can be factored into :
(a+b) • (a^2-ab+b^2)
here a = y and b = 1
hence , expanding y^3+1 in cubic formula ,
(y^3+1) = (y+1)(y^2-(y)(1)-1^2)
(y^3+1)=(y+1)(y^2-y+1)
putting this value of (y^3+1) in the given expression ,
= (y^4-y^3+2y^2+y-1)/(y+1)(y^2-y+1).
Trinomial cannot be factored , hence the final answer is ,
= (y^4-y^3+2y^2+y-1)/(y+1)(y^2-y+1).
