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vladimir2022 [97]
3 years ago
11

25 turned to a fraction

Mathematics
1 answer:
eimsori [14]3 years ago
5 0
The answer to your question is 1/4
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Can someone help ne with this question please
bezimeni [28]

Answer: 34

Step-by-step explanation: 2/5 = 4/10 = 12/30  This means that the machine cuts out 12m lengths for every roll now you just take 400/12 and you get your answer. Now 400/12 will be 33,333... So just round it up to how many she needs aka 34

3 0
3 years ago
What are the steps for using integer tiles to evaluate the expression 45 divided by 15
Goryan [66]
The answer is B. Hope you get it.
6 0
3 years ago
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Evaluate the expression. 7.2 + 6.3(5.4 – 6)
REY [17]

\text{Hey there!}

\text{Evaluate the expression: 7.2 + 6.3(5.4 - 6)}

\mathsf{7.2+6.3(5.4-6)}\\\\\mathsf{5.4 -6=-0.6}\\\\\mathsf{7.2+6.3(-0.6)}\\\\\mathsf{6.3(-0.6)=-3.78}\\\\\mathsf{7.2 - 3.78= \underline{3.42}}\\\\\boxed{\boxed{\mathsf{Answer:3.42}}}\checkmark

\text{Good luck on your assignment and enjoy your day!}

~\frak{LoveYourselfFirst:)}

7 0
3 years ago
Read 2 more answers
I NEED THIS DONE IN TWO HOURS :,(
Pani-rosa [81]
I hope I’m not too late. Substitute x = 4y + 5y = 2
y = 2. Substitute this value into the first equation: x + -4 x 2 = -8. So the answer is (-8,2).
3 0
2 years ago
Given the function f(x)= 14x^2 + 5x - 1 answer the question if you could change the 14 to any other number, but the rest has to
polet [3.4K]
This is a polynomial of degree 2, and remember that complex roots always come in pairs; therefore, in a second degree polynomial you can only have 0 real roots and 2 complex roots, or 2 real roots and 0 complex roots. There is no way you can have 1 real root and 1 complex root because, as stated before, complex (non-real) roots always come in pairs; so the only way of having 1 real root is dumping the polynomial of degree 2 (14 x^{2}) by changing the 14 to 0. That way we'll left with f(x)=5x-1 which only has one real root:
0=5x-1
5x=1
x= \frac{1}{5}

7 0
3 years ago
Read 2 more answers
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