All categories

2 years ago

The sum of three consecutive odd number is 153. What is the smallest of the three numbers?

Mathematics

2 answers:

shtirl [24]2 years ago

7 0

59, 51, 53
The formula you would use is
x+(x+2)+(x+4)
If you need help understanding, feel free to comment..

ad-work [718]2 years ago

6 0

First, divide 153 by 3, because there are 3 consecutive odd numbers that sum to be 153, to get a sense of where to start.

153÷3 (consecutive odd numbers)= 51

Then try adding consecutive odd numbers around 51 to get the sum of 153.

Trial and Error:

51+ 53+ 55 ≠ 153
47+ 49 + 51 ≠ 153

Then finally:

49 + 51 + 53= 153

Hope this helps!

You might be interested in

In a triangle, the measure of one angle is five more than the first and the third angle is one more than four times the first.

katrin [286]

Answer:

A= 29

B=34

C=117

Step-by-step explanation:

<u>A triangle has three sides and a triangle always adds up to be 180</u>

A + B + C = 180

B = A + 5

C = 4A + 1

Plug in.

A + A + 5 + 4A + 1 = 180

6A + 6 = 180

6A = 174

A = 29

<u>Now since you found A, find the other two by plugging A in!</u>

C = 4(29) + 1

C = 117

<u>Plug in the B equation</u>

B = 29 + 5

B=34

Check your answers

29 + 117 + 34 = 180

4 0

2 years ago

We know that narrower confidence intervals give us a more precise estimate of the true population proportion. Which of the follo

gulaghasi [49]

Answer:

A. We can select a lower confidence level and increase the sample size.

Step-by-step explanation:

The length of a confidence interval is:

Direct proportional to the confidence interval. This means that the higher the confidence level, the higher the length of the interval is.

Inverse proportional to the size of the sample.This means that the higher the size of the sample, the lower, or narrower, the length of the interval is.

Which of the following could we do to produce higher precision in our estimates of the population proportion?

We want a narrower interval. So the correct answer is:

A. We can select a lower confidence level and increase the sample size.

3 0

3 years ago

What is the slope of the line that passes through the points (9, 1) and (10, -1)? Write your answer in simplest form.

Otrada [13]

We conclude that the slope of the linear equation that passes through the points (9, 1) and (10, -1) is -2.

<h3>How to get the slope of the line that passes through the points (9, 1) and (10, - 1)?</h3>

A linear equation has the general form:

y = a*x + b

Where a is the slope of the line, and b is the y-intercept.

There is a simple equation to get the slope of a point if we know two points. For a line that passes through ( a, b) and (c, d), the equation for the slope is:

a = (d - b)/(c - a)

In this case we know that our line passes through (9, 1) and (10, -1), then using the above equation, we can see that the slope is:

a = (-1 - 1)/(10 - 9) = -2

We conclude that the slope of the linear equation that passes through the points (9, 1) and (10, -1) is -2.

If you want to learn more about linear equations:

brainly.com/question/1884491

#SPJ1

7 0

1 year ago

Use DeMoivre's theorem to evaluate the expression

natima [27]

Answer:

B. $\dfrac{9}{2}-i\dfrac{9\sqrt{3}}{2}$

Step-by-step explanation:

DeMoivre's theorem:

If the complex number $z=r(\cos \alpha+i\sin\alpha),$ then for natural number n

$z^n=r^n(\cos n\alpha+i\sin n\alpha).$

In your case,

$z=\sqrt{3}\left(\cos\dfrac{5\pi}{12}+i\sin\dfrac{5\pi}{12}\right)$

and you have to evaluate $z^4.$

By DeMoivre's theorem,

$z^4=(\sqrt{3})^4\left(\cos 4\cdot \dfrac{5\pi}{12}+i\sin 4\cdot \dfrac{5\pi}{12}\right)=9\left(\cos \dfrac{5\pi}{3}+i\sin\dfrac{5\pi}{3}\right)=9\left(\dfrac{1}{2}-i\dfrac{\sqrt{3}}{2}\right)=\dfrac{9}{2}-i\dfrac{9\sqrt{3}}{2}.$

7 0

2 years ago

How do you prove the two triangles congruent?

bazaltina [42]

5 ideas
1.SSS (side, side, side) SSS stands for "side, side, side" and means that we have two triangles with all three sides equal. ...
2.SAS (side, angle, side) ...
3.ASA (angle, side, angle) ...
4.AAS (angle, angle, side) ...
5.HL (hypotenuse, leg)

3 0

3 years ago