Choice-d is an example of a plane, but doesn't describe it.
Answer:
Part a)
tex]V = -1 \times 10^8 Volts[/tex]
Part b)
Part c)
Explanation:
Part a)
Net charge distribution on each shell is given as
On surface of radius "a"
on radius "b"
on radius "c"
Now potential at the outer shell is
Part b)
Since copper sphere is a conducting sphere so here it will be an equi potential surface
So the potential will remain same throughout the surface of this sphere
Now we can say
Part c)
Now electric potential at inner sphere is given as
The magnitude of the magnetic field on the axis of the ring 5 cm from its center is 143 pT.
The radius of the nonconducting ring is R = 10 cm.
The ring is uniformly charged q = 10 μC.
The angular speed of the ring, ω = 20 rad/s
The ring is x = 5 cm from the center of the ring.
Now,
R = 10 cm = 0.1 m
q = 10.0 μC = 10 × 10⁻⁶ C
x = 5 cm = 0.05 m
The magnetic field on the axis of a current loop is given as:
B = [ μ₀ IR² ] / [4π(x² + R²)^{3/2} ]
Now, I = q / [2π/ω]
So, the magnitude of the magnetic field which is directed away from the center is:
B = [ μ₀ ωqR² ] / [4π(x² + R²)^{3/2} ]
B = [ μ₀ (200) (10 × 10⁻⁶) (0.1)² ] / [4π((0.05)² + (0.1)²)^{3/2} ]
B = 1.43 × 10⁻¹⁰ T
B = 143 pT
Learn more about the magnetic field here:
brainly.com/question/14411049
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-- Most of the southern part of the state is considered to have
no risk of damage.
-- Most of the upper part of the state is considered to be at risk
for only minor damage.
-- A tiny part of the state, in the 'Big Bend' region in the west, is
considered to be at risk for moderate damage.
d(t) = 1.1t² + t + 1
The constant speed required to cover the same distance between t = 3 to t = 5 is the same as the average speed over that same time interval. It is given by:
v = Δx/Δt
v = average speed, Δx = change in distance, Δt = elapsed time
Given values:
Δx = d(5) - d(3) = 19.6ft
Δt = 5s - 3s = 2s
Plug in and solve for v:
v = 19.6/2
v = 9.8ft/s
