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Dmitry_Shevchenko [17]
3 years ago
9

When a wool cloth is rubbed on the surface of a balloon, it tends to give away electrons causing the surface of the balloon to b

ecome :
positively charged
negativity charged
neutrally charged
Physics
2 answers:
Law Incorporation [45]3 years ago
4 0

Answer:

It is negativity charged

Shalnov [3]3 years ago
4 0

Answer:

positively charged

Explanation:

a wool has neutral charges hence when rubbed against a balloon it will generate positive charges

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3 years ago
What is the energy of a photon of blue light with a wavelength of 460 nm?
kaheart [24]

Answer: E=4.321(10)^{-19} J

Explanation:

The energy E of a photon is given by:

E=h\nu (1)

Where:

h=6.626(10)^{-34}\frac{m^{2}kg}{s} is the Planck constant

\nu is the frequency light

On the other hand, there is an inverse relationship between \nu  and the wavelength \lambda:

\nu=\frac{c}{\lambda} (2)

Where:

c=3(10)^{8} m/s is the speed of light

\lambda=460 nm=460(10)^{-9}m is the wavelength

Substituting (2) in (1):

E=\frac{hc}{\lambda} (3)

E=\frac{(6.626(10)^{-34}\frac{m^{2}kg}{s})(3(10)^{8} m/s)}{460(10)^{-9}m}

Finally:

E=4.321(10)^{-19} J This is the energy of a photon of blue light, in Joules.

4 0
3 years ago
How does the kinetic energy of an object relate to its mass and velocity?
Setler [38]

The kinetic energy of an object is directly proportional to its mass, and to the square of its velocity.

5 0
3 years ago
What do you need to measure speed?
Furkat [3]

Answer:

The equation for speed is : distance divided by time.

Hoped I helped-

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7 0
4 years ago
Un tubo metálico tiene 100 metros de longitud cuando está a 0 oC y 100,13 metros cuando se calienta hasta 100 oC. ¿Cuál es el co
Artyom0805 [142]

Answer:

 α= 1.3 10-5 ºC⁻¹

Explanation:

La dilatación termica de los cuerpos esta dada por la relación  

      ΔL = L₀ α ( T -T₀)

en este caso nos piden el coeficiente de dilatación térmica

     α =DL/L₀ DT

calculemos

      α = (  100,13 -100)/[100 (100 – 0)]

       α = 1,3 10-5 ºC⁻¹

Traduction

The thermal expansion of bodies is given by the relationship

       ΔL = L₀ α (T -T₀)

in this case they ask us for the coefficient of thermal expansion

        α = ΔL / L₀ ΔT

    let's calculate

        α = (100,13 -100) / [100 (100 - 0)]

        α= 1.3 10-5 ºC⁻¹

6 0
3 years ago
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