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3 years ago

In photosynthesis, carbon dioxide is converted to oxygen and then released.

Physics

2 answers:

3241004551 [841]3 years ago

7 0

What is the question yes it is converted to and then released

Korvikt [17]3 years ago

4 0

There are options on this question are: True or False. The answer should be true. Because the photosynthesis carbon dioxide it can converted to oxygen and it will be released. Hope it helped you, and have a great day. -Charlie :)

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which element are you most likely to find as a free element rather than a compound lead or calcium, explain?

TEA [102]

Pb, if compared to Ca it is less reactive and it is a transition metal, and is highly stable alone.

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3 years ago

Anuja is holding a stuffed dog, with a mass of 0.30 kg, when Derek decides that he wants it and tries to pull it away from Abuja

igor_vitrenko [27]

Answer:

a = 3.33 m/s²

Explanation:

The horizontal acceleration of the dog can be found by using Newton's Second Law of Motion as follows:

F = ma

where,

F = Unbalanced force applied on the dog = 11 N - 10 N = 1 N

m = mass of the dog = 0.3 kg

a = horizontal acceleration of dog = ?

Therefore,

1 N = 0.3 kg(a)

a = 1 N/0.3 kg

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3 years ago

A pendulum consists of a stone with mass m swinging on a string of length L and negligible mass. The stone has a speed of v0 whe

Dmitriy789 [7]

Answer:

(a) $v = \sqrt{ mv_0^2 - 2gL(1-\cos(\theta))}$

(b) $\theta = \arccos(\frac{2gL-v_0^2}{2gL})$

Explanation:

(a) The total mechanical energy of the system is conserved.

$K_A + U_A = K_B + U_B\\\frac{1}{2}mv_0^2 + 0 = \frac{1}{2}mv^2 + mgh \\h = L - L\cos(\theta) = L(1 - \cos\theta)\\\frac{1}{2}mv^2 = \frac{1}{2}mv_0^2 - mgL(1-\cos(\theta))\\v^2 = mv_0^2 - 2gL(1-\cos(\theta))\\v = \sqrt{ mv_0^2 - 2gL(1-\cos(\theta))}$

(b) The conservation of energy states

$K_A + U_A = K_M + U_M\\\frac{1}{2}mv_0^2 + 0 = 0 + mgL(1-\cos(\theta))\\1-\cos(\theta) = \frac{v_0^2}{2gL}\\\cos(\theta) = 1-\frac{v_0^2}{2gL} = \frac{2gL-v_0^2}{2gL}\\\theta = \arccos(\frac{2gL-v_0^2}{2gL})$

(c) As explained in part (a) the total mechanical energy of the system is equal to the initial kinetic energy, since the potential energy of the system at that point is zero.

$E_{total}= K_A + U_A = K_A + 0\\E_{total} = \frac{1}{2}mv_0^2$

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3 years ago

A 40.0 kg box is placed on a 2.00 m tall shelf. If the box falls off the shelf, what is its kinetic energy as it strikes the gro

RUDIKE [14]

M = 40 Kg , g=9.8 m/s² , h = 2 m

PE = m g h

PE = (40) (9.8) (2)

PE = 784 J

KE = PE

½m v² = m g h

½ v² = g h

½ v² = (9.8) (2)

½ v² = 19.6

v² = 19.6×2

v² = 39.2

V = √39.2

V = 6.26 m/s

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KE = ½(40) (6.26)²

KE =783.8 J

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3 years ago

Coulomb’s law is similar to what other law in physics?

Gemiola [76]

Universal law of gravitation

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3 years ago

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