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3 years ago

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If the average time it takes for the cart from point 1 to point 2 is 0.2 s, calculate the angle θ from the horizontal of the tra

ck. Assume the track is frictionless. Hint: use the definitions of acceleration and Newton’s second law.

1 answer:

inn [45]3 years ago

5 0

Answer:

hehe

Explanation:

I dont know because I am a noob ant study

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I NEED THE RIGHT ANSWER FOR THIS ASAP NO LINKS !!!

raketka [301]

Answer:

it is the dependent since it keeps changing over time get it :)

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3 years ago

An average person can reach a maximum height of about 65 cm when jumping straight up from a crouched position. During the jump i

Yakvenalex [24]

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a. Initial speed is zero from a crouching position...

b... Mass of body * 9.8

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3 years ago

A ball is thrown straight up. It passes a 2.00-m-high window 7.50 m off the ground on its path up and takes 1.30 s to go past th

OLga [1]

Answer:

u = 13.67 m/s

Explanation:

given,

window height = 2 m

window is 7.5 m off the ground on its path up

total distance from the ground to pass the window = 2 + 7.5 = 9.5 m

time taken to go past the window = 1.30 s

using equation of motion

$S = u t +\dfrac{1}{2}gt^2$

$(2+7.5)= u\times 1.3 -0.5\times 9.8\times 1.3^2$

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3 years ago

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4 years ago

Read 2 more answers

at what position an object be placed in front of a concave mirror of radius of curvature 40cm so that an erect image of magnific

Thepotemich [5.8K]

C=40cm
f=C/2=40/2=20

m=3

$\\ \sf\longmapsto m=\dfrac{f}{f-u}$

$\\ \sf\longmapsto 3=\dfrac{20}{20-u}$

$\\ \sf\longmapsto 3(20-u)=20$

$\\ \sf\longmapsto 60-3u=20$

$\\ \sf\longmapsto 3u=40$

$\\ \sf\longmapsto u=13.3cm$

m=magnification
f is focal length
C is radius of curvature
u is object distance

8 0

3 years ago