Answer: a) Case 2 b) Case 1
Explanation:
a) By definition, the magnitude of a torque, referred to a given point, is expressed as the product of the force that causes the torque, times the perpendicular distance to the reference point.
If we assume that the only force acting on the arm is the weight of the arm, and that this is concentrated in a point in the center of it (taking the arm as a solid bar with the center of mass at the mid-point), clearly the torque will be the greatest when the force be exactly perpendicular, which is the case of the arm placed straight out parallel to the ground (Case 2).
b) As the torque and the angular acceleration are directly proportional each other (being the rotational inertia the proportionality constant) the angular acceleration will be maximum when torque be maximum also, which is the case that the arm begins to swim, due to the perpendicular distance to the shoulder is the maximum possible (Case 1).
Answer:
Speed
Explanation:
If a vehicle hit any other object then its speed will slow down or some time the vehicle will stop its depends on the force exerted by other object on the vehicle.
The change in speed of vehicle is due to momentum because momentum is always conserved. So to conserve the momentum the speed of the vehicle decreases because after hitting the overall mass is increases.
Answer:
Net force is the vector sum of forces acting on a particle or body. ... Its associated torque, the net force, becomes the resultant force and has the same effect on the rotational motion of the object as all actual forces taken together. It is possible for a system of forces to define a torque-free resultant force.
Explanation:
In a tug of war, a fat man pulls with a force of 100 N on one side, and a man pulls with 90 N on the other side. Compute the net force.
Solution:
Given:
Force F1= 100 N,
Force F2 = -90 N.
The net force formula is given by,
F_NET = F_1 + F_2F
N
ET=F
1
+F
2
F_NET = (100 ) +(– 90)F
N
ET=(100)+(–90)
F_NET= 10 NF
N
ET=10N
Therefore, the net force is 10 N.
According to Boyle-Mariotte:
p₁V₁=p₂V₂=>V₂=p₁V₁/p₂= 0.0024*101.70/ 84.16=0.0028 m³
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