Answer:
Eyeglass lenses will almost always be convex on the outer surface, the one farthest from the eye, simply to fit it to the curvature of the face.
Explanation:
Hope this helped Mark BRAINLIEST!!!
Answer:
i think 692m/s2 is the correct answer
Answer: The answer to the path of a bot I am not sure if
Explanation:RRest
Answer:
The magnification of a virtual image is -0.33
Explanation:
We can calculate the magnification as the ratio of height of the image to the height of the object. It can be also stated as the ratio of size of the image obtained to the original size of the object. Also this ratio can be equated to the ratio of image distance to object distance. So magnification can be termed as ratio of image distance to object distance. As in the present case, the image distance or the distance of the formation of image from the lens is 10 cm and the distance of object from the lens or the object distance is 30 cm. Then,
.
So, the image will be diminished to 0.33 times the original size as the magnification of the virtual image is obtained as -0.33.
Answer:
for the body to float, the density of the body must be less than or equal to the density of the liquid.
Explanation:
For a block to float in a liquid, the thrust of the liquid must be greater than or equal to the weight of the block.
Weight is
W = mg
let's use the concept of density
ρ_body = m / V
m = ρ_body V
W = ρ_body V g
The thrust of the body is given by Archimedes' law
B = ρ_liquid g V_liquid
as the body floats the submerged volume of the liquid is less than or equal to the volume of the block
ρ_body V g = ρ_liquid g V_liquid
ρ_body = ρ liquid Vliquido / V_body
As we can see, for the body to float, the density of the body must be less than or equal to the density of the liquid.