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DerKrebs [107]
3 years ago
5

1.- Un barco recorre la distancia que separa Gran Canaria de Tenerife (90 km) en 6 horas. ¿Cuál es

Physics
1 answer:
bezimeni [28]3 years ago
7 0

Answer:

The speed is 15 km/h or 4.16 m/s.

Explanation:

A boat travels the distance that separates Gran Canaria from Tenerife (90 km) in 6 hours. Which  the speed of the boat in km / h? And in m / s?

Given that,

Distance, d = 90 km = 90000 m

Time, t = 6 hours = 21600 s

Speed = distance/time

v=\dfrac{90\ km}{6\ h}\\\\=15\ km/h

or

v=\dfrac{90000\ m}{21600\ s}\\\\=4.16\ m/s

So, the required speed is 15 km/h or 4.16 m/s.

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Are glasses lenses concave or convex?
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Answer:

Eyeglass lenses will almost always be convex on the outer surface, the one farthest from the eye, simply to fit it to the curvature of the face.

Explanation:

Hope this helped Mark BRAINLIEST!!!

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3 years ago
A car hits a tree with a force of 45 N, the mass of the tree is 65g. What is the resulting acceleration?
bekas [8.4K]

Answer:

i think 692m/s2 is the correct answer

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3 years ago
A 1.72 kg block is released from rest on a 16.31 degree frictionless incline. The object proceeds down the incline to the horizo
Ilya [14]

Answer: The answer to the path of a bot I am not sure if

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5 0
3 years ago
What is the magnification of a virtual image if the image is 10.0 cm from a lens and the object is 30 cm from the lens
7nadin3 [17]

Answer:

The magnification of a virtual image is -0.33

Explanation:

We can calculate the magnification as the ratio of height of the image to the height of the object. It can be also stated as the ratio of size of the image obtained to the original size of the object. Also this ratio can be equated to the ratio of image distance to object distance. So magnification can be termed as ratio of image distance to object distance. As in the present case, the image distance or the distance of the formation of image from the lens is 10 cm and the distance of object from the lens or the object distance is 30 cm. Then, Magnification =-\frac{Image distance}{Object distance}=-\frac{10}{30}=-0.33.

So, the image will be diminished to 0.33 times the original size as the magnification of the virtual image is obtained as -0.33.

5 0
3 years ago
Read 2 more answers
While the block hovers in place, is the density of the block (top left) or the density of the liquid (bottom center) greater?
Licemer1 [7]

Answer:

for the body to float, the density of the body must be less than or equal to the density of the liquid.

Explanation:

For a block to float in a liquid, the thrust of the liquid must be greater than or equal to the weight of the block.

Weight is

        W = mg

let's use the concept of density

        ρ_body = m / V

        m = ρ_body V

        W = ρ_body V g

The thrust of the body is given by Archimedes' law

        B = ρ_liquid g V_liquid

 

as the body floats the submerged volume of the liquid is less than or equal to the volume of the block

       ρ_body V g = ρ_liquid g V_liquid

     

       ρ_body = ρ liquid Vliquido / V_body

As we can see, for the body to float, the density of the body must be less than or equal to the density of the liquid.

3 0
4 years ago
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