Answer:
Explanation:
given,
radius of curve = 166 m
angle of the banked road = 11°
mass of car = 736 Kg
speed of the curve = 81 km/h
= 81 x 0.278 = 22.52 m/s
normal force acting on the tires
on tire there will be two force acting on it
first one will be force acting due to weight and the other force acting on the tire is due to centripetal force.
Answer:
Well,
Explanation:
In a wave, energy is transported without the transport of water. Basically, a wave can be described as a disturbance that travels through a medium, transporting energy from one location to another location without transporting matter.
ANSWER
B - Air density is lower, so there is less heat transfer
EXPLANATION
We want to identify why temperature decreases with higher altitude.
When radiation is absorbed by the earth's surface, it heats the surroundings and the air through convection and conduction.
However, as we ascend higher into the atmosphere, the amount of solar radiation absorbed by the troposphere's gases decreases significantly.
Due to less heat transfer, air molecules start to move away from each other causing a decrease in air density
Hence, we see that temperature decreases with increasing altitude because there is less heat transfer due to the lower air density.
The answer is option B.
Answer:
Magnitude of the acceleration = 1.90 m/s²
Direction of the acceleration = 65.1° (measured counter clockwisely from the +x axis) or 65.1° north of East
Explanation:
The net force is the vector sum of all the forces acting on the sailboat.
One force is due to the action of the water on the hull of the boat and is directed east and has a magnitude of 1990 N; in vector form, F₁ = (1990j) N
The other force is due to the action of the wind on the sails and is directed northeast with a magnitude of 2440 N; in vector form, F₂ = 2440 [(cos 45°)î + (sin 45°)j] N = 1725î + 1725j) N
Net force = F₁ + F₂ = 1990j + (1725î + 1725j) = (1725î + 3715j) N
According to Newton's law, Net force causes acceleration of A body,
Net force = ma
a = (Net force)/m
a = (1725î + 3715j)/2160 = (0.80î + 1.72j) m/s²
Magnitude of acceleration
/a/ = √[(0.8²) + (1.72²)] = 1.90 m/s²
Direction of the acceleration = tan⁻¹ (1.72/0.8) = 65.1°
