Answer:
The passenger train traveled at a speed of 25 miles/hour
Step-by-step explanation:
In this question, we are asked to calculate the rate at which a particular passenger train is traveling.
We use the information in the question to answer as follows;
Firstly, we identify that they traveled at the same time but their distances are different. This means that their speed must be different also.
Mathematically, we know that time can be calculated as distance/ time.
Let us say the speed at which the passenger train traveled is x miles per hour. This means that the speed of the freight train which was 5 miles per hour slower would be (x-5) miles per hour.
We know their times are equal;
Hence;
100/x = 80/(x-5)
We cross multiply
100(x-5) = 80x
100x -500 = 80x
100x-80x = 500
20x = 500
x = 500/20
x = 25 miles per hour
Step-by-step explanation:
a)
dy/dx = 4x √(1 − y²)
Separate the variables:
dy / √(1 − y²) = 4x dx
Integrate:
sin⁻¹ y = 2x² + C
Solve for y:
y = sin(2x² + C)
b)
Plug in initial value.
4 = sin(0 + C)
Sine cannot be greater than 1, so there is no solution.
Answer:
the suface area is 9 for the one on the right and for the left 106821
Step-by-step explanation:
Answer:
4,589,200
Step-by-step explanation:
