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SCORPION-xisa [38]
4 years ago
14

A leading medical journal claims that 68% of high school students experience anxiety just before an exam. A school counselor wan

ts to conduct a survey to verify this with the students in her school and wants to do so with a margin of error (ME) of ±7%. What minimum sample size, rounded to the nearest whole person, does the counselor need to use? Hint: ME equals plus or minus two times square root of start fraction p hat left parenthesis one minus p hat right parenthesis over N end fraction end square root, where p hat is the yes proportion in the sample and N is the sample size.
N ≥ 175
N ≥ 178
N ≥ 200
N ≥ 262
Mathematics
1 answer:
BigorU [14]4 years ago
5 0
The answer is N<span>≥ 178. I just had this question and that was right.</span>
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Dionne can fold 175 packing boxes in 50 minutes. Elias can fold 120 packing boxes in 40 minutes. Who has the faster folding rate
lapo4ka [179]

Answer:

Dionne :)

Step-by-step explanation:

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3 years ago
An investment of $6,599.20 earns 4.2% interest compounded monthly over 7 years. Approximately how much interest is earned on the
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3 years ago
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HELP ASAP: Can you draw a quadrilateral that's not a parallelogram with only one pair of congruent angles? Explain why one pair
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4 years ago
Frank, who lives in Texas, and his sister Lilly, who lives in Japan, correspond regularly. From what he can tell from the postma
Hoochie [10]

Question:

The available options are:

(A) There is convincing evidence that there is no difference in the mean delivery times.

(B) There is convincing evidence that there is a difference in the mean delivery times.

(C) There is convincing evidence that the mean delivery time from Japan to Texas is greater than the mean delivery time from Texas to Japan.

(D) There is not convincing evidence that the mean delivery time from Japan to Texas is greater than the mean delivery time from Texas to Japan. (E) The t-test cannot be used for sample sizes that are this small.

Answer:

The correct option is;

(A) There is convincing evidence that there is no difference in the mean delivery times.

Step-by-step explanation:

Here we have the formula for the two-sample t-test given s;

t =\frac{\overbar\overline{\rm x}_1 - \overbar\overline{\rm x}_2 }{\sqrt{\frac{\sigma ^2_1}{n_1} } +\frac{\sigma ^2_2}{n_2} }}    

To Texas N₁ = 12,  \overline{\rm x}_1 =8.74 σ₁ = 2.92 SE Mean₁ = 0.84

To Japan N₂ = 9  \overline{\rm x}_2 = 6.75 σ₂ = 2.56 SE Mean₁ = 0.85

t =   1.667

Where the null hypothesis is

mu To Texas = mu To Japan and the alternative is

mu To Texas > mu To Japan

Here since the observed P value of P = 0.058 is greater than the significance level of 0.05 we fail to reject the null hypothesis and we will therefore, not accept the alternative hypothesis.

Hence, there is convincing evidence that there is no difference in the mean delivery times.  

3 0
3 years ago
Find the correct sum of each geometric sequence.
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3 years ago
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