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slava [35]
2 years ago
8

Solve the following equation 7 • 10^n = 7000

Mathematics
1 answer:
marysya [2.9K]2 years ago
3 0

Answer:

N=3

Step-by-step explanation:

7.10^n =7000

10^n =1000

10^n = 10^3

(coz bases are the same powers are equal)

Therefore n =3

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Write an inequality that expresses the range in the volume of acceptable tennis balls.
Rudik [331]

Answer:

the smallest number is the lower bound and the largest number is the upper bound, your inequality would be

8.2 ≤ x ≤ 9.5, where x represents the volume of tennis balls.

4 0
3 years ago
What is the slope of a line that passes through the points (-4,0) and (0,4)?
CaHeK987 [17]

Answer:

The slope is the change in Y over the change in X.

m = (0 - 3) / (0 - (-4)) = -3 / +4 = -0.75

4 0
2 years ago
Evaluate 10m+n/4 wnen m=5 and n=16
solmaris [256]
Hi!

Let's put the values in the equation.

10 · 5 + 16 ÷ 4 = ?

Using PEMDAS...

Multiplication
50 + 16 ÷ 4 = ?

Division
50 + 4 = ?

Addition
54

The answer is 54

Hope this helps! :)
4 0
3 years ago
Read 2 more answers
A population of rabbits in a lab, p(x), can be modeled by the function p(x) = 20(1.014)x , where x represents the number of days
Nitella [24]

Answer:

20 = initial population of the rabbits

1.014 = growth rate of the rabbits

the average rate of change from day 50 to day 100 is 0.8

Step-by-step explanation:

A population of rabbits in a lab, p(x), can be modeled by the function

p(x) = 20(1.014)^x

This model is exponential. Where 20 = initial population of the rabbits

1.014 = growth rate of the rabbits with 1.4% increase rate of the rabbits

To find the average rate of change from day 50 to day 100,

find the population p(50) and p(100). Subtract them and divide by 100 - 50 = 50. 

p(50) = 20(1.014)50 = 40.08... 

p(100) = 20(1.014)100 = 80.32... 

(80.32 - 40.08) / (100 - 50) = 40.24/50 = 0.8048. which is approximately 0.8 to the nearest tenth. 

The rate of change is 0.8. 

7 0
3 years ago
Josh estimates the height of his desk. What is a reasonable estimate?
cestrela7 [59]
1.5 meters tall is a good estimate
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3 years ago
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