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IgorC [24]
3 years ago
7

Lines J and k are perpendicular. The slope of line k is 3. Which equation is true?

Mathematics
2 answers:
Lerok [7]3 years ago
4 0
The answer is A.
Multiplying perpendicular slopes results in -1. Multiply the slope of j by the slope of k(3) to get -1.
julia-pushkina [17]3 years ago
3 0

Answer:

the answer must be A. 3. slope of j=1

Step-by-step explanation:

i did on the usa test prep

get some brainlest

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7 + X = 2x - 5<br> 7<br> Solve<br> 3
Anna11 [10]

Answer:

x=12

Step-by-step explanation:

7+x=2x-5

12=1x

x=12

8 0
3 years ago
HELP! WILL GIVE BRANLIEST!
Brrunno [24]
6x+x-8=90 because right angle
7x=98 combine like terms
7x/7=98/7
X=14
m<1=6*14=84
m<2=14-8=6
8 0
2 years ago
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How do you solve these equations? I don't want you to answer all of them, just tell me how to solve each type of equation on the
miss Akunina [59]

Answer:

8. Identify the common denominator; express each fraction using that denominator; combine the numerators of those rewritten fractions and express the result over the common denominator. Factor out any common factors from numerator and denominator in your result. (It's exactly the same set of instructions that apply for completely numerical fractions.)

9. As with numerical fractions, multiply the numerator by the inverse of the denominator; cancel common factors from numerator and denominator.

10. The method often recommended is to multiply the equation by a common denominator to eliminate the fractions. Then solve in the usual way. Check all answers. If one of the answers makes your multiplier (common denominator) be zero, it is extraneous. (10a cannot have extraneous solutions; 10b might)

Step-by-step explanation:

For a couple of these, it is helpful to remember that (a-b) = -(b-a).

<h3>8d.</h3>

\dfrac{5}{x+2}+\dfrac{25-x}{x^2-3x-10}=\dfrac{5(x-5)}{(x+2)(x-5)}+\dfrac{25-x}{(x+2)(x-5)}\\\\=\dfrac{5x-25+25-x}{(x+2)(x-5)}=\dfrac{4x}{x^2-3x-10}

___

<h3>9b.</h3>

\displaystyle\frac{\left(\frac{x}{x-2}\right)}{\left(\frac{2x}{2-x}\right)}=\frac{x}{x-2}\cdot\frac{-(x-2)}{2x}=\frac{-x(x-2)}{2x(x-2)}=-\frac{1}{2}

___

<h3>10b.</h3>

\dfrac{3}{x-1}+\dfrac{6}{x^2-3x+2}=2\\\\\dfrac{3(x-2)}{(x-1)(x-2)}+\dfrac{6}{(x-1)(x-2)}=\dfrac{2(x-1)(x-2)}{(x-1)(x-2)}\\\\3x-6+6=2(x^2-3x+2) \qquad\text{multiply by the denominator}\\\\2x^2-9x+4=0 \qquad\text{subtract 3x}\\\\(2x-1)(x-4)=0 \qquad\text{factor; x=1/2, x=4}

Neither solution makes any denominator be zero, so both are good solutions.

8 0
3 years ago
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stellarik [79]

Answer: 1.25664 or if you want in fraction form it's 2π/5

Step-by-step explanation:

To convert degrees to radians, multiply by π /180°

72° ⋅ π/180° =  72π/180 = 2π/5

Therefor, the answer is 2π/ 5 or in decimal form 1.25664.

* Hopefully this helps:) Mark me the brainliest:)

∞ 234483279c20∞

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3 years ago
4=(1/2)^× solve for x
cricket20 [7]
4=\left(\frac{1}{2}\right)^x\\&#10;2^2=2^{-x}\\&#10;x=-2&#10;
4 0
3 years ago
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