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tatuchka [14]
4 years ago
13

1. Which word best describes how you feel when working on a math assessment? ( point)

Mathematics
2 answers:
Archy [21]4 years ago
8 0

Answer:

math is really a difficult subject for me. sometimes i feel confident when i get my answers correct, but sometimes i feel bored when i dnt get my answer. Sometimes i feel anxious , sometimes i feel excited to solve the problems.

Alisiya [41]4 years ago
7 0

Answer:

excited nd anxious

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A coin bank contains only quarters and dimes. The total value of the coins in the bank is $8.80. If the dimes were quarters and
masha68 [24]

Answer:

  • 18 dimes

Step-by-step explanation:

Let the number of dimes be d and quarters be q

<u>The value is $8.80 = 880¢, so:</u>

  • 10d + 25q = 880 ⇒ 2d + 5q = 176

<u>If the dimes were quarters and the quarters were dimes, the coins' total value would be $7.30 or 730¢</u>

  • 25d + 10q = 730 ⇒ 5d + 2q = 146

<u>Now we have 2 equations. Solving the system by elimination, subtract 5 times the second equation from twice the first equation:</u>

  • 2(2d + 5q) - 5(5d + 2q) = 2(176) - 5(146)
  • 4d - 25d = -378
  • -21d = -378
  • d = -378/-21
  • d = 18
8 0
3 years ago
(a) Use the reduction formula to show that integral from 0 to pi/2 of sin(x)^ndx is (n-1)/n * integral from 0 to pi/2 of sin(x)^
Sedbober [7]
Hello,

a)
I= \int\limits^{ \frac{\pi}{2} }_0 {sin^n(x)} \, dx = \int\limits^{ \frac{\pi}{2} }_0 {sin(x)*sin^{n-1}(x)} \, dx \\&#10;&#10;= [-cos(x)*sin^{n-1}(x)]_0^ \frac{\pi}{2}+(n-1)*\int\limits^{ \frac{\pi}{2} }_0 {cos(x)*sin^{n-2}(x)*cos(x)} \, dx \\&#10;&#10;=0 + (n-1)*\int\limits^{ \frac{\pi}{2} }_0 {cos^2(x)*sin^{n-2}(x)} \, dx \\&#10;&#10;= (n-1)*\int\limits^{ \frac{\pi}{2} }_0 {(1-sin^2(x))*sin^{n-2}(x)} \, dx \\&#10;= (n-1)*\int\limits^{ \frac{\pi}{2} }_0 {sin^{n-2}(x)} \, dx - (n-1)*\int\limits^{ \frac{\pi}{2} }_0 {sin^n(x) \, dx\\&#10;&#10;
I(1+n-1)= (n-1)*\int\limits^{ \frac{\pi}{2} }_0 {sin^{n-2}(x)} \, dx \\&#10;I= \dfrac{n-1}{n} *\int\limits^{ \frac{\pi}{2} }_0 {sin^{n-2}(x)} \, dx \\&#10;

b)
\int\limits^{ \frac{\pi}{2} }_0 {sin^{3}(x)} \, dx \\&#10;= \frac{2}{3} \int\limits^{ \frac{\pi}{2} }_0 {sin(x)} \, dx \\&#10;= \dfrac{2}{3}\ [-cos(x)]_0^{\frac{\pi}{2}}=\dfrac{2}{3} \\&#10;&#10;&#10;&#10;&#10;

\int\limits^{ \frac{\pi}{2} }_0 {sin^{5}(x)} \, dx \\&#10;= \dfrac{4}{5}*\dfrac{2}{3} \int\limits^{ \frac{\pi}{2} }_0 {sin(x)} \, dx = \dfrac{8}{15}\\&#10;&#10;&#10;&#10;&#10;&#10;

c)

I_n=  \dfrac{n-1}{n} * I_{n-2} \\&#10;&#10;I_{2n+1}=  \dfrac{2n+1-1}{2n+1} * I_{2n+1-2} \\&#10;= \dfrac{2n}{2n+1} * I_{2n-1} \\&#10;= \dfrac{(2n)*(2n-2)}{(2n+1)(2n-1)} * I_{2n-3} \\&#10;= \dfrac{(2n)*(2n-2)*...*2}{(2n+1)(2n-1)*...*3} * I_{1} \\\\&#10;&#10;I_1=1\\&#10;&#10;




3 0
4 years ago
2. After the American Revolution why was there a need to establish a stable banking system?
lora16 [44]

Answer:

Federalists wanted a

centralized banking

system and Alexander

Hamilton, as Secretary of

the Treasury, proposed a

national bank in 1789.

• Antifederalists, like

Thomas Jefferson,

opposed this plan.

– They favored a

decentralized banking

system in which states

established and

regulated banks within

their borders.

Step-by-step explanation:

5 0
3 years ago
Solve the following equation <br><br> 2x-y=17<br> X-y=10
Oduvanchick [21]
You can isolate y on both sides, getting:
2x-17=y  and    x-10=y

Then, make the two y equal each other, and solve the equation
2x-17=x-10

The answer would be x=7. 
then, plut in the amount into one of the equations:
x-y=10
7-y=10
y=-3
T

Therefore, the answer is x=7 and y = -3, or (7,-3)
4 0
4 years ago
Read 2 more answers
A person is raising money to go on the marching band's spring tour. He needs to raise $600. So far he has raised $570. What perc
STALIN [3.7K]
95% would be the answer
6 0
3 years ago
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