<span>At least one bear was sighted on 28 separate days in 40 day period total = 28/40
We're looking for the daily frequency of bear sightings, that's in the whole 40 day period.
Let's say 40 days period = 100%.
Then what's 28 days?
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So the solution we're looking for would be (<span><span>28 days∗100) / </span>40 days = 70%</span>
The final answer is B. 70%.
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Answer:
18 weeks
Step-by-step explanation:
80+15x=350
15x=270
x=270/15
x=18
So if you have r^2 + 4s and r=4 and s = 1.5 r^2 is 4^2 which is 16 and 4s is 1.5 x 4 which is 6 so you do 16 + 6 which is 22 so the correct answer is a.
<span>Since the paddock assumes a rectangular shape the area is 1/2 * b * h.
From Pythagorean AB^2 = BC^2 + AC^2
(3)^2 = (x + 0.4)^2 + x^2
9 = x^2 + 0.8x + 0.16 + x^2
So 2x^2 + 0.8x + 0.16 - 9 = 0
2x^2 +0.8x- 8.84 = 0
Using the quadratic formula
The solutions are 1.911 and -2.31
The area therefore is
area=1/2 * b * h
=1.91*2.31/2 = 2.21km²
1hectare = 0.01km²
2.21km^2 = 221ha</span>
Answer:
m=16/17
Step-by-step explanation:
8(3m-2)-7m=0
24m-16-7m=0
17m-16=0
17m=16
m=16/17
